Answer is A) Al4C3 + 3H2O -> CH4 + 4Al(OH)3
One the left side there are 3 carbon atoms, or moles of carbon, and on the write side there is only one.
In order to solve these problems, count the number of atoms on each side and make sure that for each element, the number of atoms are equal.
For example, for the last problem, we have 1 zinc atom on each sidde, two hydrogen atoms, and two chlorine atoms.
Please give me brainleist. :)
Answer:
2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.
2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.
2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.
2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.
3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.
3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.
3c. It would shift to the right in order to get rid of the excess form products from it.
3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.
4a. K=[N2O4(g0] / [NO2(g)]2
4b. (Below)
K=[N2O4(g)] / [NO2(g)]2
0.4 / 0.5(2)
0.4/0.25 = 1.6
Keq= 1.6
Phosphoric acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that phosphoric acid can undergo when it's dissolved in water is given below
Explanation:
Many acids contain two or more ionizable hydrogens. There are two in carbonic acid, H₂CO₃, and three in phosphoric acid, H ₃PO ₄. For any such multiple hydrogen acid, the first hydrogen is most easily removed, and the last hydrogen is removed with the greatest difficulty. These acids are called polyprotic (many protons) acids. The multiple acid ionization constants for each acid measure the degree of dissociation of the successive hydrogens.
Step 1
Polyprotic acid is an acid that can donate two or more H+ ion per molecule. Sulfurous acid donates two hydrogen ions in an aqueous solution.
Step 2
Dissociation of sulfurous acid in aqueous solution takes place in two steps. In the first step, one H⁺ ion is donated during dissociation forming HSO₃⁻.
H₂SO₃₍aq₎ +H₂O₍₁₎→HSO₃⁻₍aq₎
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Step 3
In the second step, one H+ ion is donated from HSO3- ion f...
H₂SO₃₍aq₎ +H₂O₍₁₎→SO₃²⁻₍aq₎+H₃O⁺₍aq₎
Al2(SO4)3 + 3CaCl2 > 2AlCl3 + 3CaSO4
