Answer:
The answer is a. I learned that they can multiply by using your cells
The volume of SO2 produced at 325k is calculated as below
calculate the moles of SO2 produced which is calculated as follows
write the reacting equation
K2SO3 +2 HCl = 2KCl +H2O+ SO2
find the moles of HCl used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles
by use of mole ratio between HCl to SO2 which is 2:1 the moles of SO2 is therefore = 0.411 /2 =0.206 moles of SO2
use the idea gas equation to calculate the volume SO2
that is V=nRT/P
where n=0.206 moles
R(gas constant) = 0.082 L.atm/ mol.k
T=325 K
P=1.35 atm
V=(0.206 moles x 0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2
Answer:
![\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%200.3%20%5C%20mol%20%5C%20NaNO_3%7D%7D)
Explanation:
Molarity is a measure of concentration in moles per liter.
![molarity= \frac{moles \ of \ solute}{liters \ of \ solution}](https://tex.z-dn.net/?f=molarity%3D%20%5Cfrac%7Bmoles%20%5C%20of%20%5C%20solute%7D%7Bliters%20%5C%20of%20%5C%20solution%7D)
The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
- molarity= 1.2 mol NaNO₃/L
- liters of solution=0.25 L
- moles of solute =x
![1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}](https://tex.z-dn.net/?f=1.2%20%5C%20mol%20%5C%20NaNO_3%2FL%3D%20%5Cfrac%7Bx%7D%7B0.25%20%5C%20L%7D)
We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.
![0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L](https://tex.z-dn.net/?f=0.25%20%5C%20L%20%2A1.2%20%5C%20mol%20%5C%20NaNO_3%2FL%3D%5Cfrac%7Bx%7D%7B0.25%20%5C%20L%7D%20%2A0.25%20%5C%20L)
![0.25 \ L *1.2 \ mol \ NaNO_3/L=x](https://tex.z-dn.net/?f=0.25%20%5C%20L%20%2A1.2%20%5C%20mol%20%5C%20NaNO_3%2FL%3Dx)
The units of liters cancel, so we are left with the units moles of sodium nitrate.
![0.25 *1.2 \ mol \ NaNO_3=x](https://tex.z-dn.net/?f=0.25%20%20%2A1.2%20%5C%20mol%20%5C%20NaNO_3%3Dx)
![0.3 \ mol \ NaNO_3=x](https://tex.z-dn.net/?f=0.3%20%5C%20mol%20%5C%20NaNO_3%3Dx)
There are 0.3 moles of sodium nitrate.
Answer:
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