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Delicious77 [7]
2 years ago
14

Math questions plz help 10-11b

Mathematics
1 answer:
evablogger [386]2 years ago
6 0
Question number 10 is the same as the previous questions add them up and make them equal to 180 degrees, and then solve for the x variable.

For the second part of the question, simply plug in the value of x for each expression for R and S.






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I need help thank you.
Darina [25.2K]

Answer:

The answers and steps are in the picture

6 0
2 years ago
If m angle GEF is thirteen less than five times m angle DEG and m angle DEF = 149º, find m angle GEF. ​
Nina [5.8K]

Answer:

122*

122 degrees

Step-by-step explanation:

m∠GEF is 13 less than 5 times m∠DEG and m∠DEF = 149*

Solution:

As per given data,

m∠GEF = 5m∠DEG - 13* … (i)

m∠DEF = 149* -> m∠GEF + m∠DEG = 149* .. (ii)

Substituting value of m∠GEF in (ii)

We get,

(5m ∠DEG - 13*) + m∠DEG = 149*

6m ∠DEG - 13* = 149*

6m ∠DEG = 149* + 13* = 162*

m∠DEG = * = 27*

Substituting value of m∠DEG in (i)

We get,

m∠GEF = 5(27*) - 13*

m∠GEF = 135* - 13* = 122*

7 0
2 years ago
Pam scores n goals. Leo scored 5 fewer than Pam. Write an expression in simplest form to represent the total number of goals sco
Naddik [55]

Answer:

h

Step-by-step explanation:

3 0
3 years ago
76 + 4= add the ones and the tens. Do you regroup? yes or no
nikklg [1K]
76 + 4 is 80... don't know what you're asking
6 0
3 years ago
Incomes in a certain town are strongly right-skewed with mean $36,000 and standard deviation $7000. a random sample of 75 househ
Svet_ta [14]
Since the sample is greater than 10, we can approximate this binomial problem with a normal distribution.

First, calculate the z-score:

z = (x - μ) / σ = (37000 - 36000) / 7000 = 0.143

The probability P(x > 37000$) = 1 - P(<span>x < 37000$), 
therefore we need to look up at a normal distribution table in order to find 
P(z < 0.143) = 0.55567 
And 
</span>P(x > 37000$) = 1 - <span>0.55567 = 0.44433

Hence, there is a 44.4% probability that </span><span>the sample mean is greater than $37,000.</span>

4 0
3 years ago
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