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Delicious77 [7]
3 years ago
14

Math questions plz help 10-11b

Mathematics
1 answer:
evablogger [386]3 years ago
6 0
Question number 10 is the same as the previous questions add them up and make them equal to 180 degrees, and then solve for the x variable.

For the second part of the question, simply plug in the value of x for each expression for R and S.






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So yeah. . .. idk how to do this
kipiarov [429]

<em>Please </em>use for reference. Merci.

To find rate of change simply divide y/x.

hour 2: 56/2=28

hour 4: 125/4~about 31.3 or 31

hour 5: 164/5=32.8 or ~ 33

hour 8: 271/8 ~ about 34 or 33.875

hour 13: 404/13 ~ about 31 or 31.0769231

What numbers are the largest?

hours 5 and 8

Thus, the correct answer was option C.

5 0
3 years ago
What is the gcf of of -9y^2 + 6y
Valentin [98]

Answer:

3y

Step-by-step explanation:

First find the factors of the terms.  You need to then figure out how many factors match.

-9y² = -1 · 3 · 3 · y · y

6y = 2 · 3 · y

3y is the greatest common factor.

5 0
3 years ago
3. A vehicle uses 15 gallons of gasoline to travel 13 miles. At this rate, how many miles can the
Tems11 [23]
1. Start by identifying what the question wants so we are looking for miles per 1 gallon.
2. Set up a statement. When the word “per” is being used it relates to a fraction or a ratio. In this question we need to find how many miles a single gallon will give us. So set it up as miles/gallons
3. Plug in your numbers. Now our statement is 13 miles/15 gallons
4. Calculate. So do 13/15 which equals 0.86 miles per 1 gallon.
Tip: always add in words into your calculations. Mainly the units you are using so you can quickly look and know what the units will be. This will help you in upper placement math as well
5 0
3 years ago
Read 2 more answers
Al oeste de Albuquerque, Nuevo México, la carretera 40 con rumbo al este es recta y tiene una fuerte pendiente hacia la ciudad.
alexgriva [62]

Usando el concepto de pendiente, se encuentra que el cambio en la distancia horizontal es de 10 pies.

La pendiente de una reta es la <u>razón entre el cambio vertical y el cambio horizontal,</u> o sea, cual el cambio vertical cuando el cambio horizontal es de 1.

En este problema, hay que:

  • La pendiente es -100, o sea, cuando hay un desplazamiento de un pie por adelante, hay una queda de 100 pies.
  • Bajado 1000 pies, entonces, aplicando la proporción:

1 pie H -> -100 pies V

x pie H -> -1000 pies V

Aplicando la multiplicación cruzada:

-100x = -1000

100x = 1000

x = \frac{1000}{100}

x = 10

El cambio en la distancia horizontal es de 10 pies.

Un problema similar es dado en brainly.com/question/24766917

3 0
2 years ago
Which of these statements is true? (Select all that apply.) Any translation can be replaced by two reflections. Any translation
prisoha [69]
The second one I think.
4 0
1 year ago
Read 2 more answers
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