3 years ago

Math questions plz help 10-11b

1 answer:

6 0

Question number 10 is the same as the previous questions add them up and make them equal to 180 degrees, and then solve for the x variable.

For the second part of the question, simply plug in the value of x for each expression for R and S.

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Find the 9th term in a geometric sequence whose common ration is 1/3 and first term is 6

sasho [114]

Answer:

Therefore 9th term of the geometric sequence is $\frac{2}{2187}$

Step-by-step explanation:

Given first term(a) = 6

and common ratio = $\frac{1}{3}$

$T_n= ar^{n-1}$

$\therefore T_9=ar^{9-1}$

$\Leftrightarrow T_9=a r^8$

$\Leftrightarrow T_9=6\times ( \frac{1}{3}) ^8$

$\Leftrightarrow T_9=\frac{2}{2187}$

Therefore 9th term of the geometric sequence is $\frac{2}{2187}$

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4 years ago

Please help me. Do not understand it.

nignag [31]

Answer:

X=-5

Step-by-step explanation:

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3 years ago

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2x+y=3 ,<br>x + 3y = -12

mel-nik [20]

I think the answer would be 3

7 0

4 years ago

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Six hundred pictures are taken at a photo shoot. Twelve percent of the pictures are black and white. Which equation can be used

Rainbow [258]

Answer:

the answer is the first and why did you delete my answer

Step-by-step explanation:

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3 years ago

Suppose that a loan of $6000 is given at an interest rate of 9% compounded each year.

lara [203]

Answer:

$6540.00
$7128.60

Step-by-step explanation:

Each year, the balance is multiplied by (1+r) where r is the annual interest rate.

(a) Balance at the end of year 1:

$6000×1.09 = $6540

(b) Balance at the end of year 2:

$6540×1.09 = $7128.60

3 0

4 years ago

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