1.3*3=3.90
3.90*35=136.50
136.50 is all you need to provide at least three of the most expensive items.
You still have 13.50 left over
D. 3,750 mL
Because you have to convert liters to milliliters
<span>divide both sides of the equation by 2 to get:
(x + 1/4)^2 = -7/16 ***** this is your solution.
continue further to solve for x if you care to, but the problem did not require you to do this.
take the square root of both sides of the equation to get:
x + 1/4 = plus or minus sqrt(-7/16)
subtract 1/4 from both sides of the equation to get x = -1/4 plus or minus sqrt(-7/16).
since sqrt(-7/16) is the same as sqrt(7/16) * i, your solution becomes:
x = -1/4 plus or minus sqrt(7/16) * i.
your problem was to convert it to the form of (x + p)2 = q.
the solution to that is:
</span><span>(x + 1/4)^2 = -7/16 </span><span>subtract 1 from both sides of the equation to get:
2x^2 + x = -1
factor out a 2 on the left side of the equation to get:
2 * (x^2 + x/2) = -1
complete the squares on x^2 + x/2 to get:
2 * ((x+1/4)^2 - (1/16)) = -1
simplify by distibuting the multiplication to get:
2 * (x+1/4)^2 - 2*(1/16) = -1
simplify further to get:
2 * (x+1/4)^2 - 1/8 = -1
add 1/8 to both sides of the equation to get:
2 * (x + 1/4)^2 = -7/8 .
</span>
Answer:
Yea you correct, you answer is right
Now, let's say there are "b" boys and "g" gals... ok... well, we know there are 116 more boys than gals..... so, if there are "g" gals then there must be "g + 116" boys.
what's the total class? well is g + b or g + ( g + 116).
