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NikAS [45]
3 years ago
15

Rewrite y^2(9y^2+4y-9) in standard form

Mathematics
1 answer:
Margaret [11]3 years ago
8 0
Y²(9y² + 4y - 9)

Simplify.

(y² · 9y²) + (y² · 4y) + (y² · -9)

Simplify.

9y⁴ + 4y³ - 9y²

~Hope I helped!~


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Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"
Levart [38]

Answer:

\huge\boxed{f(-1) = -7}

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

  • 3(-1)^4 = 3

<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em>-1^4 = -1 (according to my calculator), and 3 \cdot -1 = -3, not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use -2^2 as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than  being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like -1^4. However, since we're substituting in -1, it looks like (-1)^4, so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in -1\cdot-1\cdot-1\cdot-1=1.

Applying this logic to our original term, 3(-1)^4:

  • 3(-1\cdot-1\cdot-1\cdot-1)
  • 3(1)
  • 3

Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: -5x^2

  • -5(-1)^2

Applying the same logic from our first term:

  • -5(-1 \cdot -1)
  • -5(1)
  • -5

Third term: 2x

  • 2(-1) = -2

-3 is just -3, no influence of x.

Combining our terms, we have 3-5-2-3.

This comes out to be -7, hence, the value of f(-1) for our function f(x)=3x^4-5x^2+2x-3 is <u>-7</u>.

Hope this helped!

4 0
3 years ago
Read 2 more answers
Your friend has prepared his mountly budget and asks you if he has overlooked anything in this planning. Which of the following
cluponka [151]
The answer is " what if the electric bill increases?"
3 0
3 years ago
Can anybody help me please
MatroZZZ [7]

Answer:

○ 4⁄6, -4⁄6

Step-by-step explanation:

Take the square root of both the denominator and numerator, and you will get the above two answers.

I am joyous to assist you anytime.

4 0
2 years ago
Rewrite the equation by completing the square. x^{2}+16x+64 = 0
Ostrovityanka [42]

Answer:

(x+8)²

Step-by-step explanation:

x² + 16x + 64 = (x+8)²

(x+8)² = (x+8)(x+8) = x*x + x*8 + 8*x + 8*8 = x² + 8x + 8x + 64

         = x² + 16x + 64

8 0
2 years ago
3. The graph of an equation intersects the y-axis at some point. What do the coordinates of the intersection indicate?
Vikki [24]

Answer:

Area: ½ × base × height

Perimeter: sum of side lengths of the triangle

of vertices: 3

Number of edges: 3

Internal angle: 60° (for equilateral)

Sum of interior angles: 180°

Step-by-step explanation:

5 0
2 years ago
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