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3 years ago

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9;(-6,5)

Mathematics

2 answers:

STatiana [176]3 years ago

7 0

The perpendicular equation is y = -3/2x - 4.

You can find this by first realizing that perpendicular lines have opposite and reciprocal slopes. So since it starts at 2/3 we flip it and make it a negative and the new slope is -3/2. Now we can use that and the point to get the y intercept using slope intercept form.

y = mx + b

5 = (-3/2)(-6) + b

5 = 9 + b

-4 = b

And now we can use our new slope and new intercept to model the equation.

y = -3/2x - 4

WARRIOR [948]3 years ago

4 0

Hay dear friend thank you for asking the question

according to the question we know that

y = mx +b

And given that y = 5 , m = -3/2, x = -6

so

5 = -3/2×(-6) +b

5 = 9 + b

-4 = b

now we can use our new slope and new intercept model equation then,

y = (-3/2)x-4

I hope it's help you

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What is 18/48 simplify

Y_Kistochka [10]

Hmm they're both even numbers so maybe we can start by cutting each number in half.
$\rm \dfrac{18}{48}=\dfrac{9\cdot2}{24\cdot2}=\dfrac{9}{24}$
18 and 48 had 2 as a common factor.
So factoring a 2 out of each number was the same as cutting each number in half. Try to do something similar with the 9 and 24. They each have something in common.

4 0

2 years ago

Read 2 more answers

I cant believe how bad my brother, Reuben, is at growing things. He bought a whole bunch of plants at the nursery the other day.

jeka94

Answer:

68 plants.

Step-by-step explanation:

Let x represent the number of plants that Reuben bought from the nursery.

We have been given that Reuben bought a whole bunch of plants at the nursery the other day. Right away, five died. So number of plant left would be $x-5$ .

We are also told that then our dog dug up 2/9 of them. So number of plants left after dug-up would be $\frac{2}{9}(x-5)$ .

Further a rabbit came and ate ½ of what was left. So number of plants left would be $\frac{\frac{2}{9}(x-5)}{2}=\frac{2}{9\times 2}(x-5)=\frac{1}{9}(x-5)$ .

Since Reuben had only 7 plants left, so we will equate our expression with 7 and solve for x as:

$\frac{1}{9}(x-5)=7$

$9\times \frac{1}{9}(x-5)=7\times 9$

$x-5=63$

$x-5+5=63+5$

$x=68$

Therefore, Reuben bought 68 plants at the nursery.

6 0

2 years ago

Noon to 3:05 elapsed time

GrogVix [38]

Noon is 12, I'm guessing you mean both of these at am, or both at pm. 12-3 is 3 hours, but there's 5 extra, so the elapsed time would be 3:05.

6 0

2 years ago

The sum of 3 and 7 times a number is 45

san4es73 [151]

Answer:

4.5

Step-by-step explanation:

The sum of 3 and 7 is 10

then what number to you multiply 10 by to get 45

45 ÷ 10 = 4.5

so the answer is 4.5

6 0

2 years ago

What is the factored form of x^3-1

polet [3.4K]

Answer:

the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

Step-by-step explanation:

We need to find factors of x^3 -1

$x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\$

So, the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

7 0

2 years ago