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nikklg [1K]
2 years ago
7

PLZ HELPPPPPPPPPPPPPPPP

Mathematics
2 answers:
Sedbober [7]2 years ago
5 0
I believe it’s 9x+1

Add all the equations/side values together
skelet666 [1.2K]2 years ago
3 0
9x+1 is the answer for this problem
You might be interested in
Which polynomial represents the sum below? 8x^2+2x+8 + 3x^3+7x+4
valkas [14]

Answer:

26 \times21 \frac = 1 > 262 {2}^{2} {?}{?}

5 0
3 years ago
How many 1/2 unit cubes can fit in a a prism with a volume of 6 cubic units
AlekseyPX

Answer:

48 cubes

Step-by-step explanation:

step 1

Find the volume of one 1/2 unit cube

The volume of the cube is given by

V=b^3

where

b is the length side of the cube

we have

b=\frac{1}{2}\ units

substitute

V=(\frac{1}{2})^3

V=\frac{1}{8}\ units^3

step 2

Divide the volume of the prism by the volume of one cube

6:\frac{1}{8}=6(8)=48\ cubes

3 0
3 years ago
I need the answer ASAP :( really struggling
pashok25 [27]
<h3>Answer: Choice A  -4 \le x \le -2</h3>

Explanation:

Ask yourself this: "When is the graph completely horizontally flat?" The answer to this question is when x is between -4 and -2. This is where the graph is constant. All other intervals are either increasing or decreasing.

Saying "The graph is constant" basically means "constant rate of change", which is another way of saying that the graph isn't changing. Constant means it stays the same.

So this is why the answer is -4 \le x \le -2

Note how only choice A has both endpoints in the negative region, so it is a quick way to spot the answer.

3 0
3 years ago
Right answer gets brainlist
sukhopar [10]

Answer:

126 square meters

Step-by-step explanation:

7 x 6 x 3. You can regroup any pair of factors to make it easier on you.

I did (7 x 6) x 3 = 42 x 3 = 126

6 0
3 years ago
On the same set of axes, use slope and y-intercept to graph each line in the system shown at right then find the points of inter
anygoal [31]

Answer:

Step-by-step explanation:

-x + 2 = 3x + 6

3x + 6 = -x + 2

4x + 6 =  2

4x = -4

x = -1

y = 1 + 2 = 3

(-1, 3)

6 0
3 years ago
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