I think it's 42 since 7x6=42
Answer:
Step-by-step explanation:
Multiplying Equation A by (1/3) and adding the result to Equation B will do the trick. Let's actually solve the problem!
Equation A: (5/3)x + 3y = 12
Equation B: 4x - 3y = 8
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(5/3 + 12/3)x = 15 Note how this has eliminated the variable
(17/3)x = 15 y.
x = (3/17)(15)
Answer:
Step-by-step explanation:
Hypotenuse^2=3^2+8^2
Hypotenuse^2=9+64=73
Hypotenuse =square root of 73
Hypptenuse =8.54
Answer:
Step-by-step explanation:
5x=y+6 --------- equ 1
2x-3y=4 -------- equ 2
5x - 6 = y
y = 5x - 6
substitute in equ 2
2x-3(5x - 6) =4
2x - 3*5x + 3*6 = 4
2x - 15x + 18 = 4
- 13x = 4 - 18
-13x = -14
x = -14/-13
x = 14/13
substitute in equ 1
5*14/13 = y+6
70/13 - 6 = y
y = ( 70 - 78)/13
y = -8/13
|DF| = |DE| + |EF|
|DF| = 9x -36
|DE| = 47
|EF| = 3x+10
Substitute:
9x - 39 = 47 + 3x + 10
9x - 39 = 3x + 57 |+39
9x = 3x + 96 |-3x
6x = 96 |:6
x = 16
Put the value of x to the equation |EF| = 3x + 10
|EF| = (3)(16) + 10 = 48 + 10 = 58
Answer: |EF| = 58
