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Marat540 [252]
3 years ago
14

,,,,,,,,,,,,,,, please help dont answer tell i upload image plz

Mathematics
2 answers:
worty [1.4K]3 years ago
6 0
The answer is 10.

√100=10
Yuki888 [10]3 years ago
6 0
The square root of 100 is 10
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Anthony is saving money to buy $240 MP3 player. Anthony starts off with $50 in his bank account and add $20 each week. State the
Mazyrski [523]

Answer:

240 = 50 + 20x

5 0
4 years ago
The students at Mill Middle School held a class election. Alyssa and Megan were the only two candidates running for class presid
Dvinal [7]
In this problem, you add 21 and 29. That results in 50 and you can either:
1. Divide 29 by 50 and multiply 100. 29/50= .58 * 100= 58% or
2. Since percentage is based on 100 and the denominator is 50, multiply the top and bottom by 2 like so.
29 x 2 =  58
---    --    -----  so that makes your percentage 58.
50 x 2 = 100

Hope this is clear enough.
7 0
3 years ago
Read 2 more answers
All the ratios that are equivalent to the ratio 12:3.
taurus [48]

Answer:

Step-by-step explanation:

12:3 = 12 divide by 3 = 4

          3 divide by 3 =  1

8 0
4 years ago
The diameter and height of this cylinder are equal to the side length, s, of the cube in which the cylinder is inscribed. What i
fiasKO [112]

Answer:

V = (π/4)s³

Step-by-step explanation:

The volume of a cylinder can be found using the formula ...

V = πr²h

In this problem, we have r=s/2 and h=s. Filling in these values, the volume is ...

V = π(s/2)²·s = (π/4)s³

3 0
3 years ago
Determine whether the equation defines y as a function of x.<br> x+y=9 and x^2+y^2=1 and x=y^2
Murrr4er [49]

Answer:

Function: x+y=9

Not Function: x^2+y^2=1    and     x=y^2

Step-by-step explanation:

Given

x+y=9

x^2+y^2=1

x=y^2

Required

Determine if y is a function of x

Solving x+y=9

x+y=9

Make y the subject of formula

y = 9 - x

<em>Hence; y is a function of x</em>

Solving x^2+y^2=1

x^2+y^2=1

Subtract x² from both sides

y^2=1 - x^2

Square root of both sides

y =\± \sqrt{1 - x^2}

This implies that

y =\sqrt{1 - x^2}     or     y =-\sqrt{1 - x^2}

<em>Because </em>y<em> can be any of those two expressions, it is not a function.</em>

Solving x=y^2

x=y^2

Reorder

y^2 = x

Take square roots

y = \±\sqrt{x}

This implies that

y = \sqrt{x}      or        y = -\sqrt{x}

<em>Because </em>y<em> can be any of those two expressions, it is not a function.</em>

4 0
3 years ago
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