The distance of the ship from the point of the origin can be determined through the trigonometric functions derived from the given distances and the angle.
If we are to draw the ship with the distances traveled in the Cartesian plane, the abscissa (x-coordinate) and the ordinate (y-coordinate) can be determined as follow:
In the second part of the journey, the angle between the x-axis and the ship should be 90-25° = 65°
x-coordinate = y(cos 65°) = 0.4226y
2nd part of y-coordinate = y(sin 65°) = 0.906y
The first part of the y-coordinate is given to be x.
Thus, the expression that can be used to determine the ship's distance from the original point is,
<em> d = sqrt ((0.4226y)² + (x+0.906y)²)</em>
The 1st, 4th, and 7th terms make an arithmetic sequence of their own. The 4th term is the average of the 1st and 7th, so ...
(1st +7th)/2 = 4th
1st + 7th = 2×4th
1st = 2×4th - 7th
The first term is ...
2*141 - 132 = 150
Hello,
h(x)= if x<3 then x+2
else -x+8
(–∞5[ U [5 –∞)=(–∞ 5]
Answer B
Tommy is studying for final exams this weekend. He will spend 1/5 of his weekend studying. What fraction of the weekend will he spend studying for each of his 4 subjects if he spends the same amount of time studying for each subject.
ANSWER: 1/5 divided by 4/1 = 1/5 x 1/4 = 1/20