PLS HELP BEING TIMED!!!!

From t = 0 to t = 5.00 min, a man stands still, and from t = 5.00 min to t = 10.0 min, he walks briskly in a straight line at a

Alex73 [517]

1) Definitions

Average velocity = change in position / total time

Average acceleration = change in velocity / total time

2) (a) Average velocity in the time interval 2.00min to 8.00 min

i) time elapsed = 8.00min - 2.00min = 6.00 min = 360 s

ii) initial position at t = 2.00: x = 0 (the man remained still until t = 5.00)

iii) final position at t = 8.00:

constant speed from t = 5.00 to t = 8.00, V = 2.20 m/s

Change in position = constant velocity × time =

time = 8.00min - 5.00min = 3.00 min = 180s

Change in position = 2.20 m/s × 180 s = 396m

iv) Compute the verage velocity

Average velocity = change in position / time elapsed = 396m / 360 s = 1.10 m/s

3) (b) Average acceleration in the time interval 2.00 min to 8.00 min

i) time elapsed: 360 s

ii) initial velocity, at t = 2.00 min: 0

iii) final velocity, at t = 8.00 min: 2.20 m/s

iv) Compute the average acceleration

Average acceleration = change in velocity / time elapsed = 2.20 m/s / 360s = 0.00611 m/s²

4) (c) Average velocity in the time interval 3.00min to 9.00min

i) time elapsed: 9.00min - 3.00min = 6.00 min = 360 s

ii) initial position, at t = 3.00 min: 0

iii) final position, at t = 9.00 min

change in position = constant speed × time

time = 9.00min - 5.00min = 4.00 min = 240s

displacement = 2.20m/s × 240s = 528m

iv) Compute the average velocity

Average velocity = 528m / 360 s = 1.47 m/s

5) (d) Average acceleration in the interval 3.00 min to 9.00 min?

i) change in velocity: 2.20 m/s

ii) time elapsed = 6.00min = 360 s

iii) compute: 2.20m/s / 360s = 0.00611 m/s²

6 (e) Sketch x versus t and v versus t, and indicate how the answers to (a) through (d) can be obtained from the graphs.

i) to do the sketches use these tables

x versus time

t -------- x

0 ------- 0

2 ------- 0

3 ------- 0

5 ------- 0

8 ------- 396

9 ------ 528

10 ----- 660

velocity versus time

t ------- v

0 ----- 0

2 ----- 0

3 ----- 0

5 ----- 0

8 ----- 2.20

9 ----- 2.20

10 --- 2.20

Here the times are in minutes and the speeds in m/s

ii) You can obtain the answers to (a) through (d) by using these facts:

- speed = slope of the graph x versus t

- acceleration = slope of the graph v versust t.

Then, for each case, take the extremes of the time intervals and find the quotient (divide) rise / run, i.e. vertical change / horizontal change, between the extreme points of your time interval.

Doing that for the graph x versus t you obtaind the average speed, and for the graph v versus t you obtain average acceleration.

5 0

3 years ago

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A set of high school student heights are normally distributed with a mean of 161 centimeters and a standard deviation of 15 cent

My name is Ann [436]

Answer:

da/;vmd<>"d s

Step-by-step explanation:

5 0

3 years ago

Tony makes sandwiches for a lunch counter. This morning he made 50 beef and cheese sandwiches, 75 ham and cheese sandwiches, and

galina1969 [7]

Tony must make approximately 9 more sandwiches.

50+75+16= 141

150-141=9

Hope this helped :)

7 0

3 years ago

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(05.07) The net of a pyramid is shown below.

mote1985 [20]

Hey. Let me help you on this one.

In order for us to solve this question, we need to break this problem apart. It will make it easier to understand.

In this problem, we see five different figures - four triangles, and one square.

If we want to get the complete net-surface area, we will need to find area of each figure individually, and then, add all values together.

Let's start with a square in the center. Formula for area of a square is $S=a*a$ . In this formula, $S$ stands for total area of a square, and stands for the length of one side.

Let's substitute the values!
$S=4*4$
$S=14$

Area of the square is 14 inches squared. Awesome! Now, let's find the area of all triangles.

We can see that one of the triangles has both measures - base, and the height. We need these two values in order for us to find the measure of the triangles.

Formula for the area of a triangle is $S= \frac{a*b}{2}$ . So, we need to multiply base length by the height length, and divide by two.

$S= \frac{4*8}{2}$
$S= \frac{32}{2}$
$S=16$

Now, we know the area of one triangle. We have three other identical triangles, and in order for us to save time, let's just multiply this number by four.
$16*4=64$

Triangles are 64 inches squared in total.
64 inches squared + 14 inches squared (square area) equals to 78 inches squared.
Answer: $78^{2}$ is the area of the figure

8 0

3 years ago

Translate the sentence into an equation.

xxTIMURxx [149]

Answer:

8b + 9 = 7

Step-by-step explanation:

8 0

1 year ago