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3 years ago

Estimate the product of 204 and 0.46 Explain what method of estimation you used and why it works.

2 answers:

8 0

The estimated product would be 100.00 because if u estimate 0.49 to 0.50 and 204 to 200, multiply it and u would get 100.00

solniwko [45]3 years ago

5 0

For sake of convenience, you can multiply them by 10,

then it will become, 2040 * 46 =93840

Now, you should divide that by 100, = 93840/100 = 93.84

Did you like that idea??

If not, you can approach for basic one...but then you have to be careful about decimal..ok

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Which statement is correct?<br> A. <br> B. <br> C. <br> D.

geniusboy [140]

Answer:

Step-by-step explanation:

Answer:

Step by Step explanation:

So since the equation says that 8 is less than the square root for b, It is correct because the square root of 72 would be 8.48528137424. Which of course 8, is less than that. But it also says that the square root of 72 is less than 9. Which based on my calculations would be correct.

6 0

4 years ago

Read 2 more answers

PLEASE PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!

Oksanka [162]

The answer is Option B $(x + 6)(x^2 + 8)$

Step-by-step explanation:

Step 1: Group the given cubic polynomial into two sections.

So polynomial can be grouped as

$(x^3 + 6x^2) + (8x + 48)$

Step 2:Find what's the common in each section.

In section $(x^3 + 6x^2)$ the come term is $x^2$

In section (8x + 48) the come term is 8

Step 3:Factor the commonalities out of the two terms.

Factoring out $x^2$ from the first section $(x^3 + 6x^2)$ , we get $x^2(x + 6)$

Factoring out 8 from the second section(8x + 48) , we will get 8(x + 6).

Step 4: Combine the factors together for terms contains the same factor,

Combining we get, $\left(x+6\right)\left(x^2+8\right)$

$\left(x+6\right)\left(x^2+8\right)$

7 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

1 year ago

How do you write -63.6-5 in a simpler form

lys-0071 [83]

Answer:

-68.6

Step-by-step explanation:

subtracting a negative from a negative is addition.

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3 years ago

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Fantom [35]

Finish the sentence..

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3 years ago