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andrew11 [14]
3 years ago
12

512, 256, 128, 64, __, __, __, ...​

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

The complete pattern is: 512, 256, 128, 64, 32, 16, 8, ( and extended ) 4, 2, 1!

I do this pattern in my head literally all the time!

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Suppose Janice has a beginning bank balance of $467. She makes one ATM withdrawal for $30 and writes 4 checks for $16.80, $22.74
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Step-by-step explanation:

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A company’s sales increased 17% this year, to $8267. What were their sales last year?
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Step-by-step explanation:

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3 years ago
Ellie, an office manager, needs to find a courier to deliver a package. The first courier she is considering charges a fee of $1
Ber [7]

Answer:

The weight of the package is 1 kilograms.

It will cost  $ 13 by both the couriers services.

Step-by-step explanation:

Let the weight of her package is x kilograms

Now, according to the question:

The charges of first Courier = $10 + $3(x)

and The charges of Second  Courier = $7 + $6(x)

Also, for x  kilograms, both the charges are equal

⇒ $10 + $3(x)   =  $7 + $6(x)

or, 10 + 3x =  7 + 6x

or, 10 -7 = 6x - 3x

⇒ 3x = 3, implies  x = 3/3 = 1

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5 0
3 years ago
Water is an example of a solvent true or false !<br> Hurry up and answer
lara [203]
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4 0
3 years ago
A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in
Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

\frac{dr}{dt} =\frac{1}{2} --- rate of the radius

\frac{dh}{dt} =-\frac{1}{3} --- rate of the height

r = 2

h = \frac{1}{3}

Required

Determine the rate of change of the cone volume

The volume of a cone is:

V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)

\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}

\frac{dV}{dt} = -\frac{88}{63}

\frac{dV}{dt} =-1.396in^3/min

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0
3 years ago
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