Question

: Find the approximate perimeter of the isosceles triangle A OPD.

Answer 1

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

$P=OP+PD+OD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

$d=\sqrt{(-6+6)^{2}+(1-7)^{2}}$

$d=\sqrt{(0)^{2}+(-6)^{2}}$

$d_O_P=6\ units$

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-1)^{2}}$

$d=\sqrt{(9)^{2}+(3)^{2}}$

$d_P_D=\sqrt{90}\ units$

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-7)^{2}}$

$d=\sqrt{(9)^{2}+(-3)^{2}}$

$d_O_D=\sqrt{90}\ units$

step 4

Find the perimeter

$P=6+\sqrt{90}+\sqrt{90}$

$P=6+9.49+9.49=24.98\ units$