All categories

3 years ago

What are the solutions to the quadratic equation 4x2 = 64?

Mathematics

2 answers:

Firlakuza [10]3 years ago

5 0

Answer:

Option 3rd is correct

x = -4 and x = 4

Step-by-step explanation:

Given the equation:

$4x^2 = 64$

Divide both sides by 4 we have;

$x^2 = 16$

Take square root both sides we have;

$\sqrt{x^2} = \pm \sqrt{16}$

Simplify:

$x = \pm 4$

Therefore, the solution for the given equation are:

x = -4 and x = 4

Zielflug [23.3K]3 years ago

3 0

The 3rd one x = -4 and x = 4.

You might be interested in

WILL GIVE BRAINLIEST

mart [117]

Answer:

well the answer would be -22500 but I dont know where you would put it on a number line

6 0

1 year ago

Read 2 more answers

What is the median of 6 8 10 12 12 15 15 20?

I am Lyosha [343]

Answer:

I think is 12..........

8 0

3 years ago

Read 2 more answers

What is the slope of the line 3x- 9y=4

vlabodo [156]

Answer:

1/3 is your answer

Step-by-step explanation:

Note that in the slope intercept form, the equation looks like: y = mx + b

Isolate the y. First, subtract 3x from both sides

3x (-3x) - 9y = (-3x) + 4

-9y = -3x + 4

Next, to fully isolate the y, divide - 9 from both siedes

(-9y)/(-9) = (-3x + 4)/(-9)

y = (-3x + 4)/-9

Simplify

y = (1/3)x - 4/9

You're slope of the line (m in y = mx + b) is 1/3

4 0

4 years ago

Read 2 more answers

−4/5 times 10/16 as a fraction in simplest form, will give branliest and 44 pts

Deffense [45]

The answers -1/2

-4/5 is -.8 and
10/16 is .625
-.8 times .625 is -.5
and -.5 in fraction is -1/2

8 0

3 years ago

Read 2 more answers

Cos pi/4 cos pi/6= 1/2(___pi/12+cos 5pi/12) fill in the blank

inessss [21]

Answer:

$\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{12})+\cos(\frac{5\pi}{12}))$

So the blank is cos.

Step-by-step explanation:

There is an identity for this:

$\cos(a)\cos(b)=\frac{1}{2}(\cos(a+b)+\cos(a-b))$

Let's see if this is fit by your left hand and right hand side:

So $a=\frac{\pi}{4}$ while $b=\frac{pi}{6}$ .

Let's plug these in to the identity above:

$\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{4}+\frac{\pi}{6})+\cos(\frac{\pi}{4}-\frac{\pi}{6}))$

Ok, we definitely have the left hand sides are the same.

Let's see if the right hand sides are the same.

Before we move on let's see if we can find the sum and difference of $\frac{\pi}{4}$ and $\frac{\pi}{6}$ .

We will need a common denominator. How about 12? 12 works because 4 and 6 go into 12. That is 4(3)=12 and 6(2)=12.

$\frac{\pi}{4}+\frac{\pi}{6}=\frac{3\pi}{12}+\frac{2\pi}{12}=\frac{5\pi}{12}$ .

$\frac{\pi}{4}-\frac{\pi}{6}=\frac{3\pi}{12}-\frac{2\pi}{12}=\frac{\pi}{12}$ .

Let's go back to our identity now:

$\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{4}+\frac{\pi}{6})+\cos(\frac{\pi}{4}-\frac{\pi}{6}))$

$\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{5\pi}{12})+\cos(\frac{\pi}{12}))$

We can rearrange the right hand side inside the ( ) using commutative property of addition:

$\cos(\frac{\pi}{4})\cos(\frac{\pi}{6})=\frac{1}{2}(\cos(\frac{\pi}{12})+\cos(\frac{5\pi}{12}))$

So comparing my left hand side to their left hand side we see that the blank should be cos.

4 0

3 years ago