Answer:
The distance from point A to the top of the building is 5
feet
The Height of the Skyscraper is 5 feet
Step-by-step explanation:
Given
Let Top point of building be point C
Also Let Base of the building be point B
Distance from point A to base B of the building AB= 5 feet
∴ It makes a Right angle triangle
Also ∠ACB = 45°
Also tan 45° = 1
Now tan ∠ACB =
∴ AB= BC =5 feet
The Height of the Skyscraper is 5 feet
Now Triangle ABC is right angle triangle with right angled at B
So by Pythagoras theorem
AC= 
The distance from point A to the top of the building is 5 feet
Answer:
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P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
</span>
<span>P(t) = P(0)[exp(-0.0202t)]</span>
The description should be a vertical line on the negative side on the grid and the vertical line should be placed on the negative 8 on the x axis.
Answer:
The equivalent expression to the given expression is ![\sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Step-by-step explanation:
The given expression is ![\sqrt[3]{32x^8y^{10}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D)
To find the equivalent expression:
![\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32x%5E8y%5E%7B10%7D%7D%3D%2832x%5E8y%5E%7B10%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We may write the above expression as below:
(using square root properties)
![=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y})](https://tex.z-dn.net/?f=%3D%282%5Csqrt%5B3%5D%7B4%7D%29%28x%5E2%5Csqrt%5B3%5D%7Bx%5E2%7D%29%28y%5E3%5Csqrt%5B3%5D%7By%7D%29)
(combining the like terms and doing multiplication )
![=2x^2y^3\sqrt[3]{4x^2y}](https://tex.z-dn.net/?f=%3D2x%5E2y%5E3%5Csqrt%5B3%5D%7B4x%5E2y%7D)
Therefore
Therefore the equivalent expression to the given expression is
