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babunello [35]
4 years ago
6

Compare the functions below.

Mathematics
2 answers:
dangina [55]4 years ago
6 0
The 1st, 4th, and 5th answers are correct
ikadub [295]4 years ago
4 0

Answer:

The true statements are:

4) As x increases on the interval [0, ∞), the rate of change of f eventually exceeds the rate of change of both g and h.

5) A quantity increasing exponentially eventually exceeds a quantity growing quadratically or linearly.


Step-by-step explanation:

f(x)=3^x+2

g(x)=20x+4

h(x)=2x^2+5x+2

1) Over the interval [2, 3], the average rate of change of g is lower than that of both f and h.

Over the interval [a,b], the average rate of change of a function "j" is:

rj=[j(b)-j(a)]/(b-a); with a=2 and b=3

rj=[j(3)-j(2)]/(3-2)

rj=[j(3)-j(2)]/(1)

rj=j(3)-j(2)

For g(x):

rg=g(3)-g(2)

g(3)=20(3)+4→g(3)=60+4→g(3)=64

g(2)=20(2)+4→g(2)=40+4→g(2)=44

rg=64-44→rg=20

For f(x):

rf=f(3)-f(2)

f(3)=3^3+2→f(3)=27+2→f(3)=29

f(2)=3^2+2→f(2)=9+2→f(2)=11

rf=29-11→rf=18

For h(x):

rh=h(3)-h(2)

h(3)=2(3)^2+5(3)+2→h(3)=2(9)+15+2→h(3)=18+15+2→h(3)=35

h(2)=2(2)^2+5(2)+2→h(2)=2(4)+10+2→h(2)=8+10+2→h(2)=20

rh=35-20→rh=15

Over the interval [2, 3], the average rate of change of g (20) is greater than that of both f (18) and h (15), then the first statement is false.


2) As x increases on the interval [0, ∞), the rate of change of g eventually exceeds the rate of change of both f and h.

False, because of f(x) is an exponential function, the rate of f eventually exceeds the rate of change of both g and h.

 

3) When x=4, the value of f(x) exceeds the values of both g(x) and h(x).

x=4→f(4)=3^4+2=81+2→f(4)=83

x=4→g(4)=20(4)+4=80+4→g(4)=84

x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54

When x=4, the value of f(x) (83) exceeds only the value of h(x) (54), then the third statement is false.


4) As x increases on the interval [0, ∞), the rate of change of f eventually exceeds the rate of change of both g and h.

True, because of f(x) is an exponential function.


5) A quantity increasing exponentially eventually exceeds a quantity growing quadratically or linearly.

True.


6) When x=8, the value of h(x) exceeds the values of both f(x) and g(x).

x=8→f(8)=3^8+2=6,561+2→f(8)=6,563

x=8→g(8)=20(8)+4=160+4→g(8)=164

x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170

When x=8, the value of h(x) (170) exceeds only the value of g(x) (164), then the sixth statement is false.

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Direct variation or not a direct variation<br><br> y=5/x
MrRissso [65]

Answer:

not direct variation

Step-by-step explanation:

The equation for x and y in direct variation is

y = kx ← k is the constant of variation

y = \frac{5}{x} is not in this form, thus not direct variation.

The equation for x and y varying inversely is

y = \frac{k}{x} ← k is the constant of variation

y = \frac{5}{x} is in this form and represents inverse variation

7 0
3 years ago
This math my graduation depends on it
In-s [12.5K]

In an arithmetic sequence, consecutive terms have a fixed distance d between them. If a₁ is the first term, then

2nd term = a₂ = a₁ + d

3rd term = a₃ = a₂ + d = a₁ + 2d

4th term = a₄ = a₃ + d = a₁ + 3d

and so on, up to

nth term = a_n = a_{n-1} + d = a_{n-2} + 2d = a_{n-3} + 3d = \cdots = a_1 + (n-1)d

so that every term in the sequence can be expressed in terms of a₁ and d.

6. It's kind of hard to tell, but it looks like you're given a₁₃ = -53 and a₃₅ = -163.

We have

a₁₃ = a₁ + 12d = -53

a₃₅ = a₁ + 34d = -163

Solve for a₁ and d. Eliminating a₁ and solving for d gives

(a₁ + 12d) - (a₁ + 34d) = -53 - (-163)

-22d = 110

d = -5

and solving for a₁, we get

a₁ + 12•(-5) = -53

a₁ - 60 = -53

a₁ = 7

Then the nth term is recursively given by

a_n = a_{n-1}-5

and explicitly by

a_n = 7 + (n-1)(-5) = 12 - 5n

7. We do the same thing here. Use the known terms to find a₁ and d :

a₁₉ = a₁ + 18d = 15

a₃₈ = a₁ + 37d = 72

⇒   (a₁ + 18d) - (a₁ + 37d) = 15 - 72

⇒   -19d = -57

⇒   d = 3

⇒   a₁ + 18•3 = 15

⇒   a₁ = -39

Then the nth term is recursively obtained by

a_n = a_{n-1}+3

and explicitly by

a_n = -39 + (n-1)\cdot3 = 3n-42

8. I won't both reproducing the info I included in my answer to your other question about geometric sequences.

We're given that the 1st term is 3 and the 2nd term is 12, so the ratio is r = 12/3 = 4.

Then the next three terms in the sequence are

192 • 4 = 768

768 • 4 = 3072

3072 • 4 = 12,288

The recursive rule with a₁ = 3 and r = 4 is

a_n = 4a_{n-1}

and the explicit rule would be

a_n = 3\cdot4^{n-1}

7 0
2 years ago
Divide by 12 nd equal 14
ICE Princess25 [194]
170 dived by 12 is 14

7 0
3 years ago
Read 2 more answers
How can i write 3.06 in standard form for scientific notation
vichka [17]
In scientific notation it would just be 3.06 x 0, it is the same thing as the regular notation.
3 0
3 years ago
Y = x + 2 and y = 2x + 3
Reil [10]
Im confused as to what you are asking!
8 0
3 years ago
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