Answer:
the equation that determines the length of the base, sorry i forgot the name of it
Step-by-step explanation:
Answer:
2) x = -2
, y = 2
3) no solution exists
Step-by-step explanation:
Solve the following system:
{-2 x - 3 y = -2
y = 2 x + 6
Hint: | Perform a substitution.
Substitute y = 2 x + 6 into the first equation:
{-2 x - 3 (2 x + 6) = -2
y = 2 x + 6
Hint: | Expand the left hand side of the equation -2 x - 3 (2 x + 6) = -2.
-2 x - 3 (2 x + 6) = (-6 x - 18) - 2 x = -8 x - 18:
{-8 x - 18 = -2
y = 2 x + 6
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for x:
{-8 x - 18 = -2
y = 2 x + 6
Hint: | Isolate terms with x to the left hand side.
Add 18 to both sides:
{-8 x = 16
y = 2 x + 6
Hint: | Solve for x.
Divide both sides by -8:
{x = -2
y = 2 x + 6
Hint: | Perform a back substitution.
Substitute x = -2 into the second equation:
Answer: {x = -2
, y = 2
Answer:
-8
Step-by-step explanation:
four times two equals eight, positive times negative equals negative, so -8
Question is: how many 84s will fit in 5376? Let's think about some easy multiples:
84 * 100 = 8400, so it's too big
84 * 10 = 840, so it might work
84 | 5376 | 10
-840
84 | 4536 | 10
-840
84 | 3696 | 10
-840
84 | 2856 | 10
-840
84 | 2016 | 10
-840
84 | 1176 | 10
-840
84 | 336
We can't fit any more 840 in 336, so we check how many 84s are in 336 and what's the remainder:
84 | 336 | 4
- 336
So there's no remainder. Now we add all the partial quotients to get the final result:
10 + 10 + 10 + 10 + 10 + 10 + 4 = <u>64
</u>It's correct, I checked it with calculator. I just hope you'll be able to read something from that, it's quite difficult to do partial dividing with no pencil and paper :)
1) 2x-1 or x=1/2
2) 5a-16 or a=16/5
