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3 years ago

the point 3,2 lies on a circle.what is the exact length of the radius of this circle if the center is located at (-1,-4)

1 answer:

5 0

You can use the distance formula to solve this.

Distance Formula:
$d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}$

I am going to use point (3,2) as point 1 and (-1,-4) as point 2
Insert the points into the formula
$d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}$
$d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}$
Solve:
$d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}$
$d = \sqrt{(-4)^2 + (-6)^2}$
$d = \sqrt{16 + 36}$
$d = \sqrt{52}$
$d = \sqrt{52} = \sqrt{4}\sqrt{13}$
$d = \sqrt{52} = 2 \sqrt{13}$
$d = 2 \sqrt{13}$
$radius = 2 \sqrt{13} = 7.2111$

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Math- Look at the picture below i will mark you as brainliest if you answer correctly.

densk [106]

Answer:

Step-by-step explanation:

Substitue 15 into the x value and complete the equation.

This is because 2,280 is the original distance. 15 would be the hours and 60 would be how many miles per hour. So we multiply 15 and 60 and get 900, this is how many total miles they have driven. But when we subtract that number from 2,280, and we get 1,380, this is how many miles they have left.

4 0

3 years ago

Read 2 more answers

Please help serious answers only

pishuonlain [190]

90-7x3

90-21=69

Ther you go have a great day

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3 years ago

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A local hamburger shop sold a combined total of 712 hamburgers and cheeseburgers on Tuesday. There were 62 more cheeseburgers so

hammer [34]

A local hamburger shop sold a total of 712 burgers on Tuesday

There are 62 more cheeseburgers than hamburgers

let cheeseburers = c
let hamburgers = h

h + 62 = c
c + h = 712

Plug in h + 62 for c

(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
2h = 650
2h/2 = 650/2
h = 325

There are 325 hamburgers sold on Tuesday

c = 325 + 62
c = 387

<em>There are 387 chesseburgers sold on tuesday </em>(in case you were wondering)

hope this helps

4 0

3 years ago

(ED. 21) Analytic Geometry Unit Test..... #3 Which point is a solution of x2 + y2 > 49 and y ≤ –x2 – 4?

sdas [7]

Answer:

We want to find a solution of the system:

x^2 + y^2 > 49

y ≤ –x^2 – 4

Here we do not have any options, so let's try to find a general solution.

First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:

(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

(0, -10)

(0, -15)

(2, -10)

etc.