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mars1129 [50]
3 years ago
15

Is this equation standard form of an ellipse or circle?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
The standard form equation for a circle is

(h-x)^2+(k-y)^2=r^2

where (h, k) is the center and r is the radius.

The standard form equation for an ellipse is

\frac{(x-h)^2}{a^2}} + \frac{(y-k)^2}{b^2} = 1

(center h, k and major and minor axes a and b)

This equation is standard form for neither, but might be general form for one.

-3x^2-3y^2-12x-12y+24=0 \\ -3(x^2+y^2+4x+4y)=-24 \\ x^2+4x+y^2+4y=8\ (complete\ the\ squares)\\ (x^2+4x+4)+(y^2+4y+4)=8+4+4\\ (x+2)^2+(y+2)^2=16 \\ Circle\ with\ radius\ 4\ and\ center\ (2,\ 2)
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In case (a) car makes 105° turn.

In case (b) car makes 75° turn.

In case (c) car makes 105° turn.

Step-by-step explanation:

Figure is redrawn To explain properly (in attachment)

Given : streets are parallel means \overline{AB} ║ \overline{CD},

             AB - 4th street , CD - 3rd street and XY - King Ave.

            ∠XLA = 75°

To find : (a) ∠XLB

              (b) ∠LMD (left onto 3rd streat means left of car)

              (c) ∠YMD (right means right side of car)

∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are  

                                     supplementary)

∠XLB + 75° = 180°

∠XLB  = 180 - 75

∠XLB = 105°

∴ In case (a) car makes 105° turn.

∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)

∠LMD = 75°

∴ In case (b) car makes 75° turn.

∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are

                                       supplementary)

∠YMD + 75° = 180°

∠YMD = 180 - 75

∠YMD = 105°

∴In case (c) car makes 105° turn.

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