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mars1129 [50]
3 years ago
15

Is this equation standard form of an ellipse or circle?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
The standard form equation for a circle is

(h-x)^2+(k-y)^2=r^2

where (h, k) is the center and r is the radius.

The standard form equation for an ellipse is

\frac{(x-h)^2}{a^2}} + \frac{(y-k)^2}{b^2} = 1

(center h, k and major and minor axes a and b)

This equation is standard form for neither, but might be general form for one.

-3x^2-3y^2-12x-12y+24=0 \\ -3(x^2+y^2+4x+4y)=-24 \\ x^2+4x+y^2+4y=8\ (complete\ the\ squares)\\ (x^2+4x+4)+(y^2+4y+4)=8+4+4\\ (x+2)^2+(y+2)^2=16 \\ Circle\ with\ radius\ 4\ and\ center\ (2,\ 2)
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PLEASE HELP!! i'm struggling sm :/
Bogdan [553]

Answer:

Check boxes 3, 4, 6, and 8.

Step-by-step explanation:

We have the equation:

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And we want to select all equations that are perpendicular to the above equation.

Remember that perpendicular lines have slopes who are negative reciprocals of each other.

Therefore, the slope of our equations must be the negative reciprocal of -3.

The negative reciprocal of -3 is 1/3. We flipped -3 to -1/3, and then multiplied by a negative.

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Therefore, we will check boxes 3, 4, 6, and 8.

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