Answer: 6928
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Explanation:
We have two areas we need to find: The area of the trapezoid and the area of the rectangle. Let's call these areas A1 and A2.
Area of Trapezoid = (height)*(base1+base2)/2
A1 = h*(b1+b2)/2
A1 = 80*(150+100)/2
A1 = 80*250/2
A1 = 20000
A1 = 10000
Area of Rectangle = (length)*(width)
A2 = L*W
A2 = 48*64
A2 = 3072
Subtract the two areas (A1-A2) to get the difference D
D = A1 - A2
D = 10000 - 3072
D = 6928
This difference D is exactly equal to the shaded area.
Answer: x=0
Step-by-step explanation: Find any equation parallel to the line.
Hope this helps you out! If you need anymore help, I am more than happy to help you out if you need it! ☺
-Karleif Jonsi-
The changing rate of the amount of water in the watering can is a constant rate of 0.15 gallon per minute.
The initial volume of water in the can at time = 0 is 5 gallons
The function will be a linear function in the form of
where
is the volume of water in the can after
minutes
is the changing rate
is the initial volume when time is 0
Substitute all the values into the form we have
Answer:
2 x54 + 2 x 54
108 + 108
216
Step-by-step explanation:
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
