Step one: ALWAYS set equation equal to zero, which in this case has already been done for us.
Step two: Figure out what formula you need to use in order to solve in this case I'd use the Quadratic formula.
a=1 b=9 c=2
Quadratic formula: Then you would plug in the information. The solve for what is underneath the square root ONLY. Since you cannot solve this any further, your final two answers are...
hello :<span> <span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at </span></span> A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36