Question

Find sin 0, sec 0, and tan 0, where is the angle shown in the figure.

Answer 1

Answer:

$Let \ base = x\\5^2 = x^2 + 4^2\\25-16 = x^2\\9 = x^2\\x = 3\\\\\\opposite = 4\\adjacent = 3\\hypotenuse = 5\\Sin \theta = \frac{opposite}{hypotenuse} = \frac{4}{5} \\\\Cos\theta = \frac{adjacent}{hypotenuse} =\frac{3}{5}\\\\Tan \theta = \frac{opposite}{adjacent} = \frac{4}{3}$