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anzhelika [568]
3 years ago
14

How many solutions are there to the equation n^2-13n=-40

Mathematics
2 answers:
Marizza181 [45]3 years ago
8 0
It has 2 real solutions which are 5 and 8
Nitella [24]3 years ago
4 0

Answer:

n = 5

n = 8

Step-by-step explanation:

n^2 - 13n = -40

Equate everything to zero

n^2 - 13n + 40 = 0

Factorise

(n - 5)(n - 8) = 0

Either

n - 5 = 0

Add 5 to both sides

n - 5 + 5 = 0 + 5

n = 5

Or

n - 8 = 0

Add 8 to both sides

n - 8 + 8 = 0 + 8

n = 8

n = 5 or

n = 8

It has two real solutions

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Mario went to a store and bought 3 slices of pizza. The guy at the register said " that would be $3.75". Mario then said "wait,
Zarrin [17]

Answer:

$5

Step-by-step explanation:

Cost per slice

3.75 / 3 = 1.25

Cost of 4 slices

1.25 * 4 = 5

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3 years ago
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PLEASE HELP ME ANSWER THIS <br><br> What is the equation for the line?
Kryger [21]

Answer:

y=4x+0  I hope that's what you were looking for

Step-by-step explanation:


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3 years ago
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What is the value of x in the equation 1/2x - 2/3 y = 30, when y = 15
hammer [34]

Answer:

Step-by-step explanation:

1/2x - 2/3 × 15 = 30

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1/2x = 30 + 10

1/2x = 40

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3 years ago
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Really need help with this plsss answer
Nutka1998 [239]
Point slope form is:

y - y_{1} = m(x - x_{1})

With y_{1} and x_{1} being the coordinate points, and m being the slope.

So the coordinate points are (4, -5), and the slope is -6 in this case.

So just substitute everything in, to get:

y - ( -5) = -6(x - 4)

Or

y + 5 = -6 (x - 4)
3 0
3 years ago
WILL GIVE BRAINLIEST!!!!!! Look at the picture of a scaffold used to support construction workers. The height of the scaffold ca
maksim [4K]

Answer:

A). PR = 16.13 ft

B). QR = 9.64 ft

Step-by-step explanation:

Part (A).

From the figure attached,

ΔPQR is a right triangle,

m(PQ) = 14 ft

m(QR) = 8 ft

By applying Pythagoras theorem,

Hypotenuse² = (Leg 1)² + (Leg 2)²

(PR)² = (PQ)² + (QR)²

(PR)² = (14)² + (8)²

PR = √260

     = 16.125

     ≈ 16.13 ft

Part (B).

If PR = 17 feet

and PQ = 14 feet

By applying Pythagoras theorem in ΔPQR,

PR² = PQ² + QR²

(17)² = (14)² + (QR)²

(QR)² = 289 - 196

QR = √93

     = 9.644

     ≈ 9.64 ft

4 0
3 years ago
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