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anzhelika [568]
4 years ago
14

How many solutions are there to the equation n^2-13n=-40

Mathematics
2 answers:
Marizza181 [45]4 years ago
8 0
It has 2 real solutions which are 5 and 8
Nitella [24]4 years ago
4 0

Answer:

n = 5

n = 8

Step-by-step explanation:

n^2 - 13n = -40

Equate everything to zero

n^2 - 13n + 40 = 0

Factorise

(n - 5)(n - 8) = 0

Either

n - 5 = 0

Add 5 to both sides

n - 5 + 5 = 0 + 5

n = 5

Or

n - 8 = 0

Add 8 to both sides

n - 8 + 8 = 0 + 8

n = 8

n = 5 or

n = 8

It has two real solutions

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