To construct a circle that circumscribes to a triangle, you would have to construct a circle that where all vertices of the triangle are on the circle. To do this you would have to construct the perpendicular bisectors of each side with your compass and straight edge. Comment on this answer if you are unsure of how to construct a perpendicular bisect (it's a long fundamental process to describe, and I wouldn't want to lecture you one something you already know). Once you have done so, set your compass point on the point where all perpendicular bisectors intersect (they should intersect in ONE point, if not you will have to redo it). Set your other compass lead on one of the vertices and spin away! If you have done this correctly, you should hit all three vertices when spinning your compass. Hope this helps!
Fun fact: the point where all perpendicular bisectors intersect is called the circumcenter
74% is grater hope i helped
Answer:
54 -3n²
Step-by-step explanation:
The square of a number (n) is represented by n². Three times that value is represented by 3n².
The relation "a is subtracted from b" is represented as ...
b - a
When 3n² is subtracted from 54, the appropriate representation is ...
54 -3n²
<span>You have the following inequality given in the problem shown above:
(x^2-1)/(x^2+5x+4)</span>≤<span>0
1. To solve it, you must factor it and then you must make the study of the signs.
2. Once you do the proccedure mentioned above, you obtain the following solutions:
-4<x<-1 -1<x</span>
≤<span>
1
3. You can graph the inaquality given in the problem, as you can see in the figure attached.</span>
1. Round 50.75 to 50 and 0.18 to 0.20.
50 x 0.2 = 10
2) Round 96 to 100 and 0.499 to 0.5
100 divided by 0.5 = 50
3a) Round 8.2 to 8, 6.7 to 7, and 0.46 to 0.50
8 x 7 divided by 0.50 = 112
3b) Round 23.4 to 20, 13.9 to 10, and 0.18 to 0.20
20 x 10 divided by 0.20 = 2,000
