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igomit [66]
4 years ago
11

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who p

lay neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Mathematics
1 answer:
PolarNik [594]4 years ago
3 0

Using the rules of probability:

P(A∩B)=P(A)+P(B)−P(A∪B) = 22/30 + 18/30 − 27/30 = 13/30 Play both.

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The estimated total,costs,y, of a child's toy is practally based on the number of batteries used x.The cost of one battery is 0.
Firdavs [7]

Answer:

y = 0.75x + 12

Step-by-step explanation:

The estimated total cost, y, of a child's toy is partially based on the number 1 point of batteries used, x. The cost of one battery is $0.75. The toy itself costs $12. Which equation represents the situation?

y = 12x + 0.75

y = 0.75x + 12

y = 12x − (775

y = 0.75x − 12

y = total cost of a child's toy

Cost of each battery = $0.75

Number of batteries = x

Cost of the toy = $12

Therefore,

total cost of a child's toy = Cost of the toy + Cost of each battery * Number of batteries

y = 12 + 0.75 * x

y = 12 + 0.75x

y = 0.75x + 12

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