Answer:
(x+4)^2 =0
Step-by-step explanation:
x2 +8x+16=0
What 2 numbers multiply to 16 and add to 8
4*4 = 16
4+4 =8
(x+4) (x+4) =0
(x+4)^2 =0
The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
The picture is kind of blurry and I can’t make out the formulas. /:
Hey there!
1/7 ÷ 2
= 1/7 ÷ 2/1
1/7 ÷ 2/1
Revert 2/1 to 1/2
1 × 1 / 7 × 2
1 × 1 = 1 ⬅ your NUMERATOR (top number)
7 × 2 = 14 ⬅ your DENOMINATOR (bottom number)
1(1) / 7(2) = 1/14
Answer: 1/14 ✅
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
Answer:
20/24
Step-by-step explanation:
let the variable be x and x-4
5/6 = x-4/x
cross multiply
5x = 6x - 24
24= x
thus, x is 24 and x-4 is 20
<u>20/24</u>