(x+2)^4=((x+2)^2)^2(x+2)^2=(x^2+2^2+2(x)(2))= x^2+4+4x (x^2+4+4x)^2=(x^2+4+4x)(x^2+4+4x) = x^4+4x^2+4x^3+4x^2+16+16x+4x^3+16x+16x^2=x^4+4x^3+4x^3+4x^2+16x^2+4x^2+16x+16x+16=x^4+8x^3+24x^232x+16
Answer:
4 + (2 + 1)2 = 4 + (3)2 = 4 + 9 = 13
<h3><u>The first number, x, is equal to 33.</u></h3><h3><u>The second number, y, is equal to 23.</u></h3><h3><u>The third number, z, is equal to 46.</u></h3>
x + y + z = 102
z = 2y
x = 10 + y
Because we have values of x and z, we can plug them into the original equation to solve for y.
10 + y + y + 2y = 102
Combine like terms.
4y + 10 = 102
Subtract 10 from both sides.
4y = 92
Divide both sides by 4.
y = 23
Now that we have a value for y, we can find the value of x and z.
z = 2(23)
z = 46
x = 10 + 23
x = 33
Answer:
every single option is a deductive reasoning as all the above hypothesis are correct.
