All categories

3 years ago

What is .4667 as a fraction

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

Answer:

4667 /10000

If you round it up it should be 1/2

You might be interested in

What is 3/7 divieded by 6 in a fraction

Bingel [31]

Answer: is 1/14
Explanation:

3 0

3 years ago

Solve for x using the distributive property. 9(5 - x) = 81 x = [?]

Ilya [14]

Answer:

$\boxed {x = -4}$

Step-by-step explanation:

Solve for the value of $x$ :

$9(5 - x) = 81$

-Use Distributive Property:

$9(5 - x) = 81$

$45 - 9x = 81$

-Subtract $45$ to both sides:

$45 - 45 - 9x = 81 - 45$

$-9x = 36$

-Divide both sides by:

$\frac{-9x}{-9} = \frac{36}{-9}$

$\boxed {x = -4}$

So, the value of $x$ is $-4$ .

8 0

3 years ago

PLEASE HELP

Mkey [24]

Answer:

1) 3,6,9

2) the pattern will keep growing around 3 multiple

3) the next pattern is 12,15

8 0

3 years ago

Which statements about the hyperbola are true? Check all that apply.

max2010maxim [7]

Answer:

1.) There is a focus at (0,4)

4.) There is an asymptote with a slope of 4/3

These are the only 2 correct.

Step-by-step explanation:

Just took the quiz od edge!

4 0

4 years ago

Read 2 more answers

12. Find the measure of each interior angle of triangle QRT.

Veseljchak [2.6K]

Answer:

$\angle QRT=125.6\°$

$\angle RTQ=6.4\°$

$\angle TQR=48\°$

Step-by-step explanation:

It is important to remember that, by definition, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

In this case we can idenfity that the angle $17x$ is an exterior angle of the triangle QRT. Then:

$17x=\angle RTQ+\angle TQR$

Where:

$\angle RTQ=2x\\\\\angle TQR=48\°$

Substituting values and solving for "x", we get:

$17x=2x+48\\\\17x-2x=48\\\\15x=48\\\\x=3.2$

Then:

$17x=17(3.2)=54.4\°\\\\\\\angle RTQ=2(3.2)=6.4\°$

The sum of the interior angles of a triangle is 180°, therefore:

$\angle QRT+\angle RTQ+\angle TQR=180$

Solving for $\angle QRT$ , we get:

$\angle QRT=180-48-6.4=125.6\°$

8 0

3 years ago