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3 years ago

6

Marissa bought 60 horns for her New Year’s Eve party for $83.40.

1 answer:

anzhelika [568]3 years ago

7 0

That would cost her $25.02

Unsure what the T/F statements are they are not included

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A triangle has an angle that measures 115°. The other two angles are in a ratio of 3:10. What are the measures of those two angl

serious [3.7K]

Answer: 15º and 50º

Explanation:

The angles in a triangle add up to 180.

180 - 115 = 65

3x + 10x = 13x

13x = 65

x = 5

3x = 15

10x = 50

5 0

3 years ago

I need help Please!

Pachacha [2.7K]

Answer:

36

Step-by-step explanation:

7 0

3 years ago

Find angle A and angle E

riadik2000 [5.3K]

Answer:

m∠A = 50°

m∠E = 50°

Step-by-step explanation:

7x - 17 and 2x + 8 are same side exterior angles. They have a sum of 180°.

7x - 17 + 2x + 8 = 180

9x - 9 = 180

9x = 189

x = 21

∠A and 7x - 17 are supplementary. ∠E and 2x + 8 are vertical angles.

m∠A + 7x - 17 = 180

m∠A + 7(21) - 17 = 180

m∠A + 147 - 17 = 180

m∠A + 130 = 180

m∠A = 50

m∠E = 2x + 8

m∠E = 2(21) + 8

m∠E = 42 + 8

m∠E = 50

8 0

3 years ago

Since the slope of a vertical line is undefined, is it possible ofr vertical lines to be parallel?

ikadub [295]

Yes, because if you have x=5 and x=10 they are parallel lines to each other.

6 0

3 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago