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Korolek [52]
3 years ago
9

Given the following data, find the weight that represents the 73rd percentile. Weights of Newborn Babies 8.2 6.6 5.6 6.4 7.9 7.1

6.5 6.0 7.8 8.0 6.8 8.8 9.3 7.7 8.8
Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer:

8

Step-by-step explanation:

Arranging the data into the increasing order

5.6 6.0 6.4 6.5 6.6 6.8 7.1 7.7 7.8 7.9 8.0 8.2 8.8 8.8 9.3

73n/100=73*15/100=10.95 is not an integer

So, the 73rd percentile is

P73= weight of (73n/100)+1

P73= weight of observation (10+1)

P73=weight of 11th observation

P73=8.

The weight that represents the 73rd percentile is 8.

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faltersainse [42]
1,2,3,4,6,12,18,36 are the factors!
8 0
3 years ago
A ship sails from harbour h on a bearing of 084 for 340 km until it reaches point P. It the sails on a bearing of 210 for 160km
sattari [20]

Answer:

QH = 227.8 km ≅ 228 km

Step-by-step explanation:

∵ The bearing from H to P is 084°

∵ The bearing from P to Q is 210°

∵ The distance from H to P = 340 km

∵ The distance from P to Q = 160 km

∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°

( 180 - 84) ⇒ interior supplementary

By using cos Rule:

(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ

(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965

∴ QH = 227.8 km ≅ 228 km

7 0
3 years ago
Read 2 more answers
Grant earns $5 for each magazine he sells.Write an equation in two variables showing the relationship between the number pf maga
slega [8]

Answer:

A=5m

Grant will make $60 from selling 12 magazines.

Step-by-step explanation:

Let m represent number of magazine sold and A represent amount of money earned.

We have been given that Grant earns $5 for each magazine he sells. So amount earned from m magazines would be 5 times m that is 5m dollars.

Now, we will equate total amount earned by Grant with A as:

A=5m

Therefore, our required equation would be A=5m.

To find the amount earned by Grant by selling 12 magazines, we will substitute m=12 in our equation as:

A=5(12)

A=60

Therefore, Grant will make $60 from selling 12 magazines.

3 0
3 years ago
If you use a 0.10 level of significance in a two-tail hypothesis test, what is your decision rule for rejecting a null hypothesi
Dovator [93]

Answer:

Our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

Step-by-step explanation:

The hypotheses would be;

Null hypothesis;H0: μ = 500

Alternative hypothesis;Ha: μ ≠ 500

Since it's two - tailed at 0.1 level of significance, then each tail will contain 5% or 0.05. From the z-table attached, the corresponding critical value of 0.05 is approximately 1.645 standard deviations from the mean.

Thus, our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

7 0
3 years ago
One member of the debate team is going to be chosen president. each member is equally likely to be chosen. the probability that
inessss [21]
Let
x-------> <span>the probability that a boy is chosen
B------> </span>number of boys in the debate team
G------> number of girls in the debate team<span>

we know that
B+G=20-----> G=20-B-----> equation 1
</span>probability that a boy is chosen=number of boys in the debate team/total of people
so
x=B/20-------> equation 2

t<span>he probability that a girl is chosen is 2/3 the probability that a boy is chosen
</span>probability that a girl is chosen=(2/3)*x
probability that a girl is chosen=G/20
(2/3)*x=G/20-----> equation 3
substitute equation 1 in equation 3
(2/3)*x=[20-B]/20----> equation 4

resolve the equations system
x=B/20
(2/3)*x=[20-B]/20

using a graph tool
see the attached figure
the solution is
x=0.6
B=12
G=20-12-----> G=8

number of boys in the debate team is 12
number of girls in the debate team is 8
the probability that a boy is chosen is 0.6 ----> 60%
the probability that a girl is chosen is 0.6*(2/3)----> 0.4---> 40%

the answer is
number of girls in the debate team is 8

7 0
3 years ago
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