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1 year ago

a bag contains 20 marbles: 5 red, 5 blue, and 10 yellow what is the possibillity that a red is randomly selected

Mathematics

2 answers:

german1 year ago

4 0

Answer:

25% or 1/4 chance.

Step-by-step explanation:

The red makes up 5 out of the 20 marbles in the bag, which translates to 1/4 or 25% chance or being picked.

Good luck! Hope this helped!

irga5000 [103]1 year ago

3 0

Answer:

25% chance or 1/4 or 5/20

Step-by-step explanation:

All of these provided answers are the same. Since there is 20 marbles and 5 are red you just do 5/20!

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Solve the system of equations.

algol [13]

8x + 5(-4x) = 24
8x - 20x = 24
-12x = 24
x = -2

y = -4(-2)
y = 8

Therefore, the point of intersection is (-2,8).

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3 years ago

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Mary leaves her house to take a walk. The graph shows the distance, d, in feet from her house that Mary is at any given time, t,

Mkey [24]

Answer:

It would be option A. 10 Minutes.

Step-by-step explanation:

If you look at the graph, the farthest point, and the time of 10 minutes meet at the point (10, 2,500)

(Really hoping this helps <3)

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3 years ago

In the geometric progression 1, 2, 4… what term is 512?

Levart [38]

The next term is double the previous term, so that the $n$ -th term is given recursively by

$\begin{cases}a_1=1\\a_n=2a_{n-1}&\text{for }n>1\end{cases}$

This rule tells us that

$a_2=2a_1$

$a_3=2a_2=2^2a_1$

$a_4=2a_3=2^3a_1$

and so on, with the explicit rule

$a_n=2^{n-1}a_1=2^{n-1}$

for $n\ge1$ .

If 512 is the $k$ -th term in the sequence, then

$512=2^{k-1}\implies\log_2512=\log_22^9=\log_22^{k-1}\implies9=k-1\implies k=10$

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3 years ago

The earth travels 584 million miles in one year it takes to go around the sun. If there are 365 days in one year what speed does

EleoNora [17]

Answer:

1000miles per hour

Step-by-step explanation:

4 0

3 years ago

Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%

beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.33$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$\sigma = 5, n = 100$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.33*\frac{5}{\sqrt{100}} = 1.165$

So the correct answer is:

1.165.

6 0

3 years ago