Hello:<span>
the equation is : y = ax+b
the slope is a : a×(-3/2) = -1......(
perpendicular to a line with a slope of -3/2)
a = 2/3 y=(2/3)x+b
the line that passes through (-2, -2) :- 2 =
(2/3)(-2)+b
b = -2/3
<span> the equation is : y = (2/3)x-2/3</span></span>
<span><span>y =(2/3)(x-1)</span></span>
Answer:
y=X+7
Step-by-step explanation:
<h3>
WWK: (what we know)</h3>
(-1, 6)
1x up 1 over 1
<h3>-----------------</h3><h3>WWN2K: (what we need to know)</h3>
y=mx+b
--------------------------
Plug 6 for y, and 1 for x.
Like this 
#
We know x is -1. 6=(-1*1)+#
6=-1+#
y=X+7
-------------------
-1*1+7=6
Answer:
D) c - 2 = 25 + c + 10√c
Step-by-step explanation:
The given equation is 
Taking square on both sides, we get
Here we used ( a+ b)^2 = a^2 + b^2 + 2ab formula.
c - 2 = 5^2 + (√c)^2 + 2(5)√c
c - 2 = 25 + c +10√c
Answer: D) c - 2 = 25 + c + 10√c
Thank you.
Start by writing out the information you know mathematically (I used S for cost of senior ticket, and C for cost of child ticket. You could use X and Y, or any other combination of letters as variables)
3s + 1c=38
3s + 2c=52
Now, you'll want to eliminate one of the variables by subtracting it out. Remember - Same sign, subtract (and therefore different sign, add).
In this case, 3s exists in the first and second equation, so it's very easy to get rid of. They're both positive, so they have the same sign (+). Same sign, subtract.
3s + 1c=38
-(3s + 2c=52)
__________
0 -1c= -14
-c=-14
C=14
Now, plug c=14 into either of the original equations.
3s + C= 38
3s + 14=38
3s=24
S=8.
So, a child ticket costs $14 and a senior ticket costs $8.
Answer:
5.714
Step-by-step explanation:
8*5= 40
40/7= 5.714
