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3 years ago

The number of plants minus 4 saved for dessert

Mathematics

1 answer:

Artemon [7]3 years ago

7 0

I think the answer is N-4

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3 years ago

Which of the following equations describes the line shown below?Check all that apply.

Lena [83]

B because it can't be c or d and also it makes more sence

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3 years ago

A tree farm owner uses a grid to mark where to plant trees in the spring. The first tree is planted at (2, 3). Each of the other

Tatiana [17]

Answer:

See attached image for the drawing of the first four trees (circled in green)

The patterns is:

x = 2+3n and y= 3+2n

Position of 7th tree is: (20,15) (circled in orange in the image)

Step-by-step explanation:

Starting at the location (2,3) the next x and y positions are given by:

x = 2+3n since the horizontal position needs to be increased by 3 units on each iteration,

and y= 3+2n since the vertical position needs to be increased by 2 units on each iteration

being n= 1 through 6 (to account for the next 6 trees that need to be planted)

With such pattern, the location of the seventh tree would be:

x = 2 + 3*6 =2 + 18 = 20

y = 3 + 2*6 = 3 + 12 = 15

That is, the point (20,15) on the plane.

Also see attached image.

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3 years ago

Which strategy would you use to find 2plus8?explain

nika2105 [10]

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4 years ago

Use differentials to estimate the amount of paint needed (in m3) to apply a coat of paint 0.04 cm thick to a hemispherical dome

pogonyaev

The amount of paint is the volume of paint needed.

The amount of paint needed is 0.065312 cubic meters

<h3>How to determine the amount of paint needed</h3>

The volume of a hemisphere is:

$V = \frac 23\pi r^3$

Differentiate the above equation

$V' = 2\pi r^2 r'$

The above equation represents the estimate of the amount of paint needed.

Where:

r represents the radius (r = 52/2 m)
r' represents the thickness (r' = 0.04 cm)

So, we have:

$V' = 2\pi r^2 r'$

$V' = 2 * 3.14 * (52/2\ m)^2 * (0.04cm)$

$V' = 2 * 3.14 * (26\ m)^2 * (0.04cm)$

Express cm as m

$V' = 2 * 3.14 * (26\ m)^2 * (0.0004m)$

$V' = 0.065312 m^3$

Hence, the amount of paint needed is 0.065312 cubic meters