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Nimfa-mama [501]
3 years ago
14

Can someone please help me with this question?? It’s really hard and once you understand it, can you please give me an explanati

on? Thanks so much!!
( number:7)

Mathematics
1 answer:
maksim [4K]3 years ago
7 0

The final answer would be -10x + 2

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Need help -5(1+2k)-8(-4+5k)
Nataliya [291]

Answer:

27 - 50k

Simplify

1. Distribute

-5 ( 1 + 2k ) - 8 ( -4 + 5k )

-5 - 10k - 8 ( -4 + 5k )

2. Distribute

-5 - 10k - 8 ( -4 + 5k )

-5 - 10k + 32 - 40k

3. Add the numbers

-5 - 10k + 32 - 40k

27 - 10k - 40k

4. Add the same term to both sides of the equation

27 - 10k - 40k

27 - 50k

6 0
3 years ago
What do you know about parallel slopes; perpendicular slopes?
sukhopar [10]

Answer:

<em>Parallel slopes</em>: two lines that has the same slopes but have different y-intercept

<em>Perpendicular slope</em>: two lines that are negative reciprocals(common) of each other

7 0
3 years ago
The first five terms of an arithmetic sequence are 8, 13/2, 5, 7/2, and 2. Which function, f(x), could be used to describe the x
juin [17]

Answer:

f(x) = 8 - 1.5x

Step-by-step explanation:

Here, we want to write a function that can be used to describe the x th term of the sequence

Mathematically, this can be calculated by looking at the numbers in the sequence

The difference between each successive term

is -1.5 ( 6.5-8, 3.5 -5)

So the formula for then x th term will be;

f(x) = 8 - 1.5x

where x refers to the number of the term , for example the 4th term

5 0
3 years ago
Read 2 more answers
A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5
Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3)  = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

=  1/3 (3*(H/L)²*Q) / h²  = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q  = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

8 0
3 years ago
Y - 4 = -2 (x+3) find missing value in the solution
devlian [24]

Answer:

Not solveable

Step-by-step explanation:

because that to solve the two unkown number you must have two equations of it in order to solve it

7 0
3 years ago
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