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Vinvika [58]
3 years ago
15

Use the partial quotient to solve 673÷5

Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0
Our answer would be 134.6
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At oxnard university, a student id consists of one letter (26 possibilities) followed by eight digits (10 possibilities). (a) ho
Anika [276]

A. We are given that the combination is 1 letter and 8 digits, so the total number of unique combinations would be the product of each possibilities.

Total unique ID’s = 26 * 10 * 10 * 10 * 10 * 10 * 10 * 10 * 10

or can also be written as

Total unique ID’s = 26 * 10^8

Solving:

Total unique ID’s = 2.6 x 10^9

 

B. Let us now calculate the total unique ID’s if there is only 1 letter followed by 3 digits.

Total unique ID’s = 26 * 10^3

Total unique ID’s = 26,000

Since there are 48,000 students and only 26,000 unique ID’s, therefore it is not enough.

<span>NO.</span>

5 0
3 years ago
HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!
sladkih [1.3K]

Answer:

the correct answer is B :) can i have brainly?

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%204%7D%7B3%7D%20%20%3D%206" id="TexFormula1" title=" \frac{x + 4}{3} = 6
Gwar [14]
Multiply both sides by 3 to cancel out the 3 in the denominator of the left side of the equal sign. You get:

x + 4 = 18

Now subtract 4 from both sides to get variables one side, constants on the other. 

x = 18 - 4
x = 14

Your answer is x = 14
8 0
4 years ago
Please answer asap
kondaur [170]

Step-by-step explanation:

A trinomial is an expression that has three terms.

Square trinomial

A square trinomial is simply a perfect square trinomial, and it is represented as:

\mathbf{a^2 + 2ab + b^2 = (a + b)^2}a2+2ab+b2=(a+b)2

Difference of square binomials

This is easily identified because, the terms of the square binomials are perfect squares.

The difference of square binomials is represented as:

\mathbf{a^2 - b^2 = (a + b)(a - b)}a2−b2=(a+b)(a−b)

Sums and difference of cubes

When cubes are added or subtracted, they can be expressed using the following

\mathbf{a^3 + b^3 = (a + b)(a^2 - ab + b^2)}a3+b3=(a+b)(a2−ab+b2) --- sum of cubes

\mathbf{a^3 - b^3 = (a - b)(a^2 + ab + b^2)}a3−b3=(a−b)(a2+ab+b2) --- difference of cubes

Read more about binomial and trinomial at:

brainly.com/question/12289266

6 0
3 years ago
I need help with this question
zepelin [54]

Answer:

205.62

Step-by-step explanation:

7 0
3 years ago
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