Answer:
4^1/3 is greatest among the given
Step-by-step explanation:
√2 , 4^1/3 , 3^1/4
Find the LCM of 2, 3 , 4= 12
i ) √2 =2^1/2 = 2^6/12=(2^6)^1/12
= (64)^1/12
ii ) 4^1/3 = 4^4/12 = (4^4)^1/12
= (256)1/12
iii )3^1/4 = 3^3/12 = ( 3³ )^1/12
= (27)^1/12
Therefore ,
(256)^1/12 > (64)^1/12 > (27)^1/12
4^1/3 > 2^1/2 > 3^1/4
4^1/3 is greatest among the given
number
The standard form for the equation of a circle is :
<span><span> (x−h)^2</span>+<span>(y−k)^2</span>=r2</span><span> ----------- EQ(1)
</span> where handk are the x and y coordinates of the center of the circle and r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :
((2+(8))/2,(-5+(-9))/2)=(5,-7)
So the point (5,-7) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(2−(5))^2+(-5−(-7))^2=9+4=13
⇒r=√13
Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :
(x-5)^2+(y+7)^2=13
False, the range is just determined by minising the lowest from the highest, but the variables can still get you the same mean, which can lead to the same standard deviation
The answer is 11 and 14/33.
Answer:
46
Step-by-step explanation:
5x = 3x - 2 + 34
5x = 3x + 32
2x = 32
x = 16
plug back in
3( 16 ) - 2
48 - 2
46
