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Naily [24]
3 years ago
7

steven can type 160 words in 2 minutes and 30 seconds at this rate, how many words can he type in 4 minutes?

Mathematics
1 answer:
Gnom [1K]3 years ago
6 0

Answer:

hello : 256 words

Step-by-step explanation:

2 minutes and 30 = (2×60)+30=150seconds

4 minutes = 4 ×60 = 240 seconds

 150seconds  →160 words

240 seconds → x ?

x = (160×240) / 150 = 38400/150= 256 words

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mezya [45]
F(-3) = (-3)²
= -3 * -3
= 9
4 0
3 years ago
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8p+8=10+7p what is the solution set
Evgesh-ka [11]
The answer is:  "p = 2" .
______________________________________________________
Explanation:
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Given:
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  " 8p + 8 = 10 + 7p " ;   Solve for "p" ; 

Subtract "7p" from each side of the equation; & subtract "8" from each side of the equation; as follows:

8p + 8 − 7p − 8 = 10 + 7p − 7p <span>− 8 ; 
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"p = 2 " ;  which is our answer.
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8 0
3 years ago
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Simplify (x − 4)(3x2 − 6x + 2). 3x3 + 6x2 − 22x + 8 3x3 − 18x2 + 26x − 8 3x3 − 18x2 − 22x − 8 3x3 + 6x2 + 22x + 8
kogti [31]

Answer:

3x^3-18x^2+26x-8

Step-by-step explanation:

(x-4)(3x^2-6x+2)

3x^3-6x^2+2x-12x^2+24x-8

3x^3-18x^2+26x-8

5 0
3 years ago
Maria has 5 Orange 7 green 3 red and 9 toothpicks in a bag. if Maria randomly selects one toothpick out of the bag what is the p
hram777 [196]

Answer: 12 out of 24, so 1/2


Step-by-step explanation:

Add 3 and 9 together since those are the desired colors, then put it out of the total (24) and simplify the fraction down. Hope this helps!

5 0
3 years ago
Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz
klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

A.

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

B.

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

C.

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0
3 years ago
Read 2 more answers
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