Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle
Answer:
86400 ways
Step-by-step explanation:
Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.
Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.
After picking the places for the women, we will now fill each gap between two women with a man.
We have 6 men. Thus, number of ways to arrange the men is 6!
Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways
In this question, we given a piece-wise function, that has different definitions depending on the domain.
Evaluate the function at x = 0.
The exercise asks for us to evaluate the function at 
We have to look at the definition, and see which definition includes . The equal sign at is on the second definition, that is:
Thus, at , the value of the function is 1, and the correct answer is given by option A.
For another example of evaluation of a piece-wise function, you can check brainly.com/question/17966003
1/3 of 30 would be 10. So 10 students walk to school.
Answer:
15 is correct...
Step-by-step explanation:
Since |NB| = |HB|
So the hypotenuse is the same.
3x = x + 10
3x - x = 10
2x = 10
x = 10/2
x = 5
|KN| = x + 10
|KN| = 5 + 10
|KN| = 15
Option A
The answer is 5, the 2 are disqualified and 5 remains
