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elena-14-01-66 [18.8K]
3 years ago
15

What is the solution set of the given equation? 4y - 6y + 9y = -2

Mathematics
2 answers:
maw [93]3 years ago
8 0
4y - 6y + 9y = -2
      -2y + 9y = -2
               7y = -2
                7      7
                 y = ⁻²/₇
tangare [24]3 years ago
6 0

Answer:

y=-\frac{2}{7}

Step-by-step explanation:

Given: 4y-6y+9y=-2

To find: The solution set of the equation.

Solution:

We have, 4y-6y+9y=-2 , and we need to find the solution set.

Now, we know that a solution set is any value of a variable in an equation which satisfies the equation. So, we need to find the value of variable, y in the given equation.

So, we have

4y-6y+9y=-2

\implies 13y-6y=-2

\implies 7y=-2

y=-\frac{2}{7}

Hence, the solution set of the equation is y=-\frac{2}{7}

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Function Q gives a puppy's weight in pounds as function of its age in months. What does each expression represent in this situat
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Answer:

Q(18) is a mathematical representation of the weight in pounds of a puppy after 18 months.

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Step-by-step explanation:

Given the expressions :

Q(18)

Q(30) = 27.5

Function Q gives a puppy's weight in pounds as function of its age in months

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A function is generally represented in the form a(x) ;

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3 years ago
An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below
madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that \mu = 79.7, \sigma = 8.4

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So between the 56th percentile and the 100 - 13 = 87th percentile.

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X - 79.7 = 0.15*8.4

X = 81

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X when Z has a p-value of 0.87, so X when Z = 1.13.

Z = \frac{X - \mu}{\sigma}

1.13 = \frac{X - 79.7}{8.4}

X - 79.7 = 1.13*8.4

X = 89

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

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