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makkiz [27]
3 years ago
11

A rectangular box is twice as long as it is wide and twice as wide as it is high. The sum of its length,

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

ok so the

the length is 20

the width is 10

the height is 5

Step-by-step explanation:

ok i got this by guess and check

twice as long as it is wide so i am saying that it is 10 wide so it would be 20 long and if it is twice as wide as it is tall then it is 5 because 10/2=5

20+10+5=35

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Answer:

B:25°

Step-by-step explanation:

Now \angle ABC gets bisected by BD.

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Since, the angle is bisected, this means that the angle is split into two equal parts or the angle is halved.

We know that one of the angles is 25^{\circ} so the other angle has to be 25^{\circ} also.

Hence, the m\angle DBC=25^{\circ}.

6 0
3 years ago
A bicycle shop advertised all mountain bikes priced at a 1/3 discount. If the original cost of the bikes is $327, what is the ne
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3 0
2 years ago
Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

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\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

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2 years ago
Two angles of a triangle have the same measure and the third one is 9 degrees greater than the measure of each of the other two.
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The largest angle should be 66°
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4. GIVEN: AC II DB, AC = DB
LUCKY_DIMON [66]

Answer:

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Step-by-step explanation:

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