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makkiz [27]
2 years ago
11

A rectangular box is twice as long as it is wide and twice as wide as it is high. The sum of its length,

Mathematics
1 answer:
seraphim [82]2 years ago
8 0

Answer:

ok so the

the length is 20

the width is 10

the height is 5

Step-by-step explanation:

ok i got this by guess and check

twice as long as it is wide so i am saying that it is 10 wide so it would be 20 long and if it is twice as wide as it is tall then it is 5 because 10/2=5

20+10+5=35

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Please help me solve this question will give you braisnlt !
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Answer:

s = 54m +160

Step-by-step explanation:

Given: The attachment

Required: Determine the equation

We start by picking any two equivalent points on the table:

(m_1,s_1) = (2,268)

(m_2,s_2) = (4,376)

Next, we determine the slope, M:

M = \frac{s_2 - s_1}{m_2 - m_1}

M = \frac{376 - 268}{4-2}

M = \frac{108}{2}

M = 54

The equation is then calculated as:

s - s_1 = M(m - m_1)

Where:

M = 54

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So, we have:

s - 268 = 54(m - 2)

Open bracket

s - 268 = 54m - 108

Collect like terms

s = 54m - 108 + 268

s = 54m +160

Hence, the equation is: s = 54m +160

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explanation

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