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makkiz [27]
2 years ago
11

A rectangular box is twice as long as it is wide and twice as wide as it is high. The sum of its length,

Mathematics
1 answer:
seraphim [82]2 years ago
8 0

Answer:

ok so the

the length is 20

the width is 10

the height is 5

Step-by-step explanation:

ok i got this by guess and check

twice as long as it is wide so i am saying that it is 10 wide so it would be 20 long and if it is twice as wide as it is tall then it is 5 because 10/2=5

20+10+5=35

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stiks02 [169]
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2 years ago
Please could someone help
Zolol [24]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Two coins, A and B, each have a side for heads and a side for tails. When coin A is tossed, the probability it will land tails-s
BlackZzzverrR [31]

Answer:

Is the number of tosses for each coin enough for the sampling distribution of the difference in sample proportions PA-PB to be approximately normal?

b. No, 20 tosses for coin A is enough, but 20 tosses for coin B is not enough.

Step-by-step explanation:

a) Data and Calculations:

The probability of coin A landing tails-side up = 0.5

The proportion of times coin A lands tails-side up (PA) = 20 * 0.5 = 10

Therefore, the probability of coin A landing heads-side up = 0.5 (1 - 0.5)  

And the proportion of times that coin A lands heads-side up = 20 * 0.5 = 10.  

The proportion on either side is equally distributed.

This is why 20 tosses for coin A is enough, since the sample proportions PA is approximately normal, symmetric, and equally distributed.  There will be equal amounts of 10 tosses (0.5 *20) for either heads-side up or tails-side up.

For coin B, the probability of landing tails-side up = 0.8

The proportion of times coin B lands tails-side up (PB) = 20 * 0.8 = 16

Therefore, the probability of coin B landing heads-side up = 0.2 (1 - 0-.8)

The proportion on either side is not equally distributed, but skewed.

This is why 20 tosses for coin B is not enough, since the sample proportions PB is not approximately normal, symmetric, and equally distributed.  There will be 16 tosses landing tails-side up (0.8*20) and only 4 tosses landing heads-side up (0.2*20).

6 0
3 years ago
In the figure to the right, ABCD is a rectangle. Find the area of △ABC, if the area of △AOD is 10.
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Assuming BOD and AOC are straight lines.

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Area of the rectangle = 40 unit²

Area of ΔABC = 1/2 x 40 
Area of ΔABC = 20 unit²
5 0
3 years ago
3x^2 + 6 - 2x + 5x - 4x^2 + 9
Over [174]
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9x + 6 - 2x + 5x - 4x^2 + 9

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2x + (-3) - 16x

-14x + (-3) is the expression?
4 0
3 years ago
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