If <em>x</em> = -1, you have
2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0
and if <em>x</em> = 0, you have
2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0
The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.
Answer:
f(x) 3x 10
Step-by-step explanation:
x = the number
the function = Three time a number plus 10.
f(x) = 3x + 10
Answer:
See attached for a "Neat" quadratic formula.
a = -1
b = 2
c = 1
x = [-2 +- sqr root( 4 -4*-1*1)] / -2
x = [-2 +- sqr root( 4 -4*-1*1)] / -2
x = [-2 +- sqr root(8)] / -2
x1 = (-2 +2.8284271247) / -2
x1 = .8284271247 / -2
x1 = -0.41421
x2 = (-2 -2.8284271247) / -2
x2 = ( -4.8284271247) / -2
x2 = 2.4142135624
So the equation has the positive solution of
2.4142135624
Step-by-step explanation: