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nikklg [1K]
3 years ago
7

A rectangular prism has a base area of 400 square inches. The volume of the prism is 2,400 cubic inches. What is the height of t

he prism? (7.9A)
Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

6

Step-by-step explanation:

2,400 divided by 400 = 6

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4-(2x-3)=3 whats the answer
Oxana [17]

Hello there.

Explanation:

↓↓↓↓↓↓↓↓↓↓

4-(2x-3)=3

First, subtract by 4 from both sides.

4-(2x-3)-4=3-4

Second, simplify.

-(2x-3)=-1

Third, divide by -1 from both sides.

\frac{-(2x-3)}{-1}=\frac{-1}{-1}

Fourth, simplify.

2x-3=1

Next, add by 3 from both sides.

2x-3+3=1+3

Then simplify.

2x=4

Therefore, divide by 2 from both sides.

\frac{2x}{2}=\frac{4}{2}

Finally, simplify.

x=2

<u><em>Answer⇒⇒⇒⇒x=2</em></u>

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

8 0
3 years ago
a camera sells for $100. this is $10 less than twice the price of the camera last year. what was the price of the camera last ye
Lesechka [4]

Answer:

55?

Step-by-step explanation:

110 would be the last year for two and then divide by two

8 0
3 years ago
I NEED HELP ASAP PLZZZZ HURRRY
AleksandrR [38]

Answer:16???

Step-by-step explanation:

8 0
3 years ago
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