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nikklg [1K]
3 years ago
7

A rectangular prism has a base area of 400 square inches. The volume of the prism is 2,400 cubic inches. What is the height of t

he prism? (7.9A)
Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

6

Step-by-step explanation:

2,400 divided by 400 = 6

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GUYS CAN SOMEONE PLEASE HELP ASAP?<br> THANKS SO MUCH ULL GIVE 40POINTS AND BRAINLIEST
zubka84 [21]

Answer:

1136/295 cm

Step-by-step explanation:

Corresponding lengths of similar figures are proportional.

If we let the radius of the second cylinder be x,

x/6.4 = 7.1/11.8

x = 6.4(7.1/11.8) = 1136/295 cm

8 0
2 years ago
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pav-90 [236]

Ending position (in order)

+ 4

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+ 3

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4 0
3 years ago
Read 2 more answers
The numbers of bags of crisps sold per day in a general shop was recorded over 13 days.
Alona [7]

I just figured it out so I’ll answer it on this account lol.

Q1 = 32, Q2 = 45, Q3 = 52

Interquartile range = 52 - 32 = 20

Range = 68 - 21 = 47

6 0
3 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
4 years ago
5.
ANTONII [103]

The greatest possible number of club members is 7

<em><u>Solution:</u></em>

Given that, local readers’ club has a set of 49 hardback books and a set of 21 paperbacks

Each set can be divided equally among the club members

To find the greatest possible number of club members, we have to find the greatest common factor of 49 and 21

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

<em><u>Greatest common factor of 49 and 21:</u></em>

The factors of 21 are: 1, 3, 7, 21

The factors of 49 are: 1, 7, 49

Then the greatest common factor is 7

Thus, the greatest possible number of club members is 7

7 0
3 years ago
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