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MakcuM [25]
3 years ago
5

Find the endpoint of the line segment with the given endpoint and midpoint.

Mathematics
2 answers:
dlinn [17]3 years ago
8 0

Answer:

(10, 2)

Step-by-step explanation:

To get from the given endpoint to the midpoint, 6 was added to x and 2 was added to y. As per the definition of a midpoint, the resulting two line segments will be congruent (first endpoint and midpoint congruent to midpoint and second endpoint). Use the same formula (x + 6, y + 2) to find the second endpoint (use the x and y of the midpoint):

(x + 6, y + 2)

(4 + 6, 0 +2)

(10, 2)

weqwewe [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Midpoint (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})\\\\(\frac{x_{1}-2}{2},\frac{y_{1}-2}{2})=(4,0)\\\frac{x_{1}-2}{2}= 4   ; \frac{y_{1}-2}{2}=0\\\\x_{1}-2=4*2 ; y_{1}-2=0\\\\x_{1}-2= 8 ; y_{1}-2=0\\\\x_{1}=8+2 ; y_{1}=0+2\\\\x_{1}=10 ; y_{1}=2\\

Endpoint  ( 10, 2)

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5x + 2y = 7
k0ka [10]
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y = x + 1 . . . (2)
Putting (2) into (1) gives
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From (2) y = 5/7 + 1 = 12/7

Therefore, solution is {(5/7, 12/7)}
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Bill has enough money to buy no more than 1/2 pound of cheese. How much cheese could he buy?
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Please Help <br><br> Factor the polynomial: x^3 + 3x - 2x - 6
madreJ [45]

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Step-by-step explanation:

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Simplify the expression 6C5.<br> a.6.<br> b. 24<br> C. 30<br> d. 720
Lana71 [14]
<h3>Answer:  A) 6</h3>

=====================================================

Explanation:

Plug n = 6 and r = 5 into the nCr combination formula

_n C _r = \frac{n!}{r!*(n-r)!}\\\\_6 C _5 = \frac{6!}{5!*(6-5)!}\\\\_6 C _5 = \frac{6!}{5!*1!}\\\\_6 C _5 = \frac{6*5*4*3*2*1}{5*4*3*2*1*1}\\\\_6 C _5 = \frac{720}{120}\\\\_6 C _5 = 6\\\\

Or you could use the shortcut

_n C _{n-1} = n\\\\

Yet another path you could take is to use Pascal's Triangle. Locate the row that starts with 1,6,... and then locate the second to last item. That value in the triangle is 6.

A real world interpretation is to consider having 6 people and you are selecting 5 of them to form a group where order doesn't matter. How many ways are there to do this? Well there are 6 such ways because there are 6 ways to leave someone out of the group.

8 0
2 years ago
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