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vesna_86 [32]
3 years ago
14

Please help meeee mmmm

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0

three=3\\\\seven\ eighths=\dfrac{7}{8}\\\\3\dfrac{7}{8}=\dfrac{3\cdot8+7}{8}=\dfrac{24+7}{8}=\dfrac{31}{8}\\\\Answer:\ \boxed{\dfrac{31}{8},\ 3\dfrac{7}{8}}

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g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained
Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                          P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of residents 65-years or older who had obtained a flu shot = \frac{28}{111} = 0.25

          n = sample of residents 65-years or older = 111

          p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } },\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

   = [ 0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } , 0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } ]

   = [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0
3 years ago
885 ÷ 4. Write the quotient and remainder
3241004551 [841]

Answer:

221 remainder 1

Step-by-step explanation:

885/4 is equal 221.25

This means that the quotient is 221, and when multiplying 221 by four gets us 884. 885 - 884 has a remainder of 1

8 0
3 years ago
Please help, thanks if you do. (WILL MARK)
Likurg_2 [28]

Answer: n-6p^2 + 2np  

Hope this helps!

Step-by-step explanation:

5 0
3 years ago
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(b) In a company, out of 20 candidates 14 men and 6 women apply for two vacancies. What is the probability that (1) both men are
Doss [256]

i hope my answer helps you and you will give me the best answer

5 0
2 years ago
Given h(x)=5x-2, find h(5)
Tomtit [17]

Answer:

h(5)=23

Step-by-step explanation:

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3 years ago
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