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frutty [35]
2 years ago
11

What are the solutions to |2x + 8| = –14?

Mathematics
2 answers:
Sholpan [36]2 years ago
8 0
|2x+8| = -14 can be rewritten as 

(2x+8) = - 14      or     -(2x+8) = -14
2x = -22                      -2x-8 = -14
x = -11                         2x = 6
                                    x = 3
The solution set is {-11,3}.


raketka [301]2 years ago
8 0
This is impossible.. Absolute value cannot be a negative..

İf the is so: |2x+8|=14


Solution:

1--- 2x+8=14 

x=3


2--- 2x+8=-14

x=-11



Good Luck:)
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Option A

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This is a great question!

The first thing we want to do here is to graph the system of " inequalities " -

\begin{bmatrix}2x+9y\le \:100\\ 9x+y\le \:54\end{bmatrix}

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2x + 10y \leq 100,\\10y \leq 100 - 2x,\\y \leq - 1 / 5x + 10\\----------\\9x + y \leq 54,\\y \leq - 9x + 54

The graphed solutions would be in the attachment. I have colored the region with which the two intersect, and the fact that we are limited to quadrant 1. In this colored region there are 3 major points, ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ). We have to determine which of these are are maximum points, as the minimum are the same. Substitute these values ( ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ) ) into the equation f( x, y ) = 10x + 4y,

f ( x, y ) = 10( 5 ) + 4( 9 ),\\f ( x, y ) = 86 -\\f ( x, y ) = 10( 0 ) + 4( 10 ),\\f ( x, y ) = 40 -\\f ( x, y ) = 10( 6 ) + 4( 0 ),\\f ( x, y ) = 60

( 5, 9 ) resulted in the greatest amount, 86. That would make it our maximum point -

<u><em>Solution = Option A</em></u>

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