All categories

2 years ago

What are the solutions to |2x + 8| = –14?

2 answers:

8 0

|2x+8| = -14 can be rewritten as

(2x+8) = - 14 or -(2x+8) = -14
2x = -22 -2x-8 = -14
x = -11 2x = 6
x = 3
The solution set is {-11,3}.

raketka [301]2 years ago

8 0

This is impossible.. Absolute value cannot be a negative..

İf the is so: |2x+8|=14

Solution:

1--- 2x+8=14

x=3

2--- 2x+8=-14

x=-11

Good Luck:)

You might be interested in

3 3/4 + 2 1/8 = (make sure you simplify the fraction)

dusya [7]

This is 5 7/8 or 47/8

5 0

2 years ago

Read 2 more answers

Help me please i will mark brainliest if correct

aksik [14]

Answer:

-11

8 = 2x + 30

8 - 30 = -22

-22 ÷ 2 = -11

x = -11

Also if you place 2×(-11) + 30 you get 8

8 0

2 years ago

Evaluate the expression below x/2 +8y-15 for x = -12 and y=3

jeka94

3 0

3 years ago

Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0

3 years ago

Solve for the angle x.

sergejj [24]

Answer:

x=45

Step-by-step explanation:

An entire triangle is 180 degrees and you already know that one angle is 90 degrees. 180 - 90 is 90. Now you have the equation 2x=90.

You then divide each side by 2 to get the x by itself which leaves you with x=45.

8 0

2 years ago

Read 2 more answers