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3 years ago

9

Temperature can be measured in two different common units: degrees Celsius and degrees Fahrenheit. fff represents the temperatur

e in degrees Fahrenheit as a function of the temperature ccc in degrees Celsius. f=32+1.8cf=32+1.8cf, equals, 32, plus, 1, point, 8, c Water freezes at 000 degrees Celsius. What is the freezing temperature of water in degrees Fahrenheit?

1 answer:

marshall27 [118]3 years ago

6 0

Answer:

Water freezes at 32 °F.

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Olivia is cutting a 1 1/2 m by 3/4 m piece of rectangular paper into two pieces along its diagonal. Find the area

netineya [11]

Answer:

9/16 m.

Step-by-step explanation:

When you cut two pieces along its diagonal it causes it to be two congruent triangular pieces.

<em>You need to multiply the length and the width to find an area: </em>

1 1/2 × 3/4

<em>Now you need to change it into an improper fraction:</em>

1*2+1 = 2+1 = 3; this gives us 3/2:

3/2 × 3/4 = 9/8 = 1 1/8

<em>Dividing it by 2:</em>

9/8 ÷ 2

8 0

3 years ago

Does anyone know how to solve this inequality algebraic-ally:

Snezhnost [94]

Answer:

-1/2 ≤ x ≤ 3

Step-by-step explanation:

hope that helps

3 0

3 years ago

Read 2 more answers

I need some helppp people

dsp73

We can observe that the function describing the graph is linear and so the equation is of linear nature:

$y=mx+n$

Numbers m and n have special names. m is called the slope, n is called y-intercept.

From the graph one can tell that the line intercepts y-axis at y = -1 that means n = -1. What about the slope you say?

The slope can be calculated using two points' coordinates that lie on the line:

$m=\frac{\Delta y}{\Delta x}=\frac{-1-5}{0-5}=\frac{6}{5}$

Now our line has an equation,

$y=\frac{6}{5}x-1$

Hope this helps.

4 0

3 years ago

Read 2 more answers

What is the equation for the plane illustrated below?

TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

$a\cdot x + b\cdot y + c\cdot z = d$

Where:

$x$ , $y$ , $z$ - Orthogonal inputs.

$a$ , $b$ , $c$ , $d$ - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0), (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

$y = m\cdot x + b$

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - x-Intercept, dimensionless.

If $x_{1} = 2$ , $y_{1} = 0$ , $x_{2} = 0$ and $y_{2} = 2$ , then:

Slope

$m = \frac{2-0}{0-2}$

$m = -1$

x-Intercept

$b = y_{1} - m\cdot x_{1}$

$b = 0 -(-1)\cdot (2)$

$b = 2$

The equation of the line in the xy-plane is $y = -x+2$ or $x + y = 2$ , which is equivalent to $3\cdot x + 3\cdot y = 6$ .

yz-plane (0, 2, 0) and (0, 0, 3)

$z = m\cdot y + b$

$m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}$

Where:

$m$ - Slope, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

If $y_{1} = 2$ , $z_{1} = 0$ , $y_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

y-Intercept

$b = z_{1} - m\cdot y_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the yz-plane is $z = -\frac{3}{2}\cdot y+3$ or $3\cdot y + 2\cdot z = 6$ .

xz-plane (2, 0, 0) and (0, 0, 3)

$z = m\cdot x + b$

$m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - z-Intercept, dimensionless.

If $x_{1} = 2$ , $z_{1} = 0$ , $x_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

x-Intercept

$b = z_{1} - m\cdot x_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the xz-plane is $z = -\frac{3}{2}\cdot x+3$ or $3\cdot x + 2\cdot z = 6$

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

$a = 3$ , $b = 3$ , $c = 2$ , $d = 6$

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

8 0

3 years ago

6 feet<br> 12 feet<br> What is the area of the given composite shape?

Reika [66]

Answer:

choice A; 128.52 square feet

Step-by-step explanation:

This shape is made up of a semi-circle and a rectangle. The area of the rectangle will be 12*6 = 72 sq ft.

The formula for area of a circle is $\pi$ * $r^{2}$ . also r=radius. We are given the diameter, 12 feet. The radius is diameter/2, so the radius of the circle will be 6 feet.

Since pi is infinite we round it to 3.14.

Plug in the values and our expression will be (3.14* $6^{2}$ )/2 because it is a semi-circle. Simplify that to (3.14*36)/2 = 113.04/2 = 56.52 sq ft.

Remember to add the area of the rectangle and semi-circle. 72 + 56.52 = 128.52 sq ft.

3 0

2 years ago