<h2>Option D: a call to a private method of the superclass</h2>
Explanation:
Option a: a method with the "same signature" is allowed in the subclass. There will not be any confusion because the object which is trying to call the method will decide whether to call the sub class or super class.
Option b: a call to a super class constructor is possible because, when you create an object of sub class automatically the super class constructor will be called. Even the sub class constructor can call the super class constructor explicitly.
Option c: A subclass can create method that's not defined by the super class
Option D: a private method is private inside the class and hence even the object of that class cannot access.
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Answer:
501.
Explanation:
In Transmission Control Protocol (TCP), sending and receiving of data is done as byte. These bytes are eventually grouped into packets referred to as segment.
The sequence number of the segment if all data is sent in only one segment is the same as the first byte of that segment.
In this scenario, a user datagram connection is sending 500 bytes to a client and the first byte is numbered 501. Thus, if all data is sent in only one segment, the sequence number of the segment is 501. The 501 represents the initial segment number (ISN).
However, assuming the same data was sent in five (5) segments. The sequence number would be;
First segment (1st) = 501.
Second segment (2nd) = 1501.
Third segment (3rd) = 2501.
Fourth segment (4th) = 3501.
Fifth segment (5th) = 4501.
Answer:
I'm sorry the answer is really difficult to understand, could you explain?
Explanation:
