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3 years ago

6010x98 equals ???????

Mathematics

2 answers:

topjm [15]3 years ago

8 0

I suggest using a calculator since it's quicker, but it's 588,980

vitfil [10]3 years ago

7 0

588980.................

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0.6x = 1.2x + 6 A) −1 B) −10 C) 1 D) 10

son4ous [18]

Answer:

x = -10

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve for x.<br> 4x +4=12

PolarNik [594]

Answer:

x = 2

Step-by-step explanation:

4x +4=12

-4. -4

4x.= 8

divide both saide by 4

x. = 2

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3 years ago

An experiment consists on rolling a fair number cube. There are 6 possible outcomes: 1, 2, 3, 4, 5, and 6. Find the probability

dimulka [17.4K]

Answer:

Step-by-step explanation:

The only possible outcomes on the die are 1,2,3,4,5,6.

Since 7 is not in the possible outcome list, It is impossible to obtain a 7 on this 6-sided die.

If the question <em>had </em>asked for the probability of other values, it would have been 1/6, because you can get each number at least once every 6 rolls. This, however varies in terms of experimental probability

Hope this helps

3 0

3 years ago

What are the square roots of 36100?

sleet_krkn [62]

$\huge\text{Hey there!}$

$\large\textsf{What are \bf the square roots of 36,100?}$

$\mathsf{\sqrt{36,100}=190\times190 = \bold{190}^2}$

$\mathsf{190^2=36,100}$

$\mathsf{(- 190)^2=36,100}$

$\mathsf{190\times190=36,100}$

$\mathsf{\sqrt{36,100}=\bf 190}$

$\mathsf{-\sqrt{36,100}=\bf -190}$

$\boxed{\boxed{\large\text{Answer: \huge \bf -190 and 190}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

3 years ago

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If a family has 6 children, in how many ways could the parents have 3 boys and 3 girls?

Jlenok [28]

The parents could have 3 boys and 3 girls in 400 ways

<h3>How to determine the number of ways?</h3>

The given parameters are

Children, n = 6

Boys, r = 3

Girls, r =3

The number of combination is:

$Ways = ^nC_{r1} *^nC_{r2}$

So, we have:

$Ways = ^6C_3 *^6C_3$

Apply the combination formula

$Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}$

This gives

Ways = 400

Hence, the parents could have 3 boys and 3 girls in 400 ways