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arlik [135]
3 years ago
6

A construction worker covered a square floor using 172.3 ft^2 of flooring without any overlap. Which

Mathematics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

Step-by-step explanation:

aye I need the answer soomeine helo me out, add my insta;, hy.cxsar

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In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?
Sophie [7]

Answer:   6π

<u>Step-by-step explanation:</u>

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

A=\pi r^2\bigg(\dfrac{\theta}{360^o}\bigg)

Given: r = 6, Ф = 60°

A=\pi (6)^2\bigg(\dfrac{60^o}{360^o}\bigg)\\\\\\.\quad =\pi (6)^2\bigg(\dfrac{1}{6}\bigg)\\\\\\.\quad =6\pi

3 0
2 years ago
What is the weight of one half of two thirds of a sack of rice? The sack of rice weighs 99 kilograms.
Eddi Din [679]
First you need to find what 2/3 equals
to do this, take 99 divided by 3
99/3=33

if 1/3 equals 33, two thirds would be 33x2
33x2=66

now, you need to find 1/2 of 66.  this can be done 2 different ways

1.    66 divided by 2    -    66/2=33
OR
2.    66 x 1/2 = 33     OR     66 x .5 = 33

The answer is 33 kilograms

6 0
3 years ago
Read 2 more answers
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
Write the expression <br> 3x-(2-4x) in standard form
Llana [10]
7x-2 is how it’s written in standard form
4 0
3 years ago
Find the length of AB
ZanzabumX [31]
AB= 45 degrees central angle theorem
8 0
2 years ago
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