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3 years ago

Guys I need the right answer ASAP look at the pic and give me the surface area the options are

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

the right answer is option D. 90 feet^2

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Cyrus is inviting 11 friends over for pizza. He would like to have enough pizza so each friend can have 1/4 of a pizza. About ho

ExtremeBDS [4]

Answer:

Cyrus needs to order 3 full pizzas to feed his 11 friends .

Step-by-step explanation:

The number of friends invited = 11

Share of pizza for each friend = 1/4 pizza

Now, as 1 friend eats 1/4 of a pizza.

⇒ 11 friends eat = $11 \times \frac{1}{4} = 2.75$

So, 11 friends can eat 2 .75 pizza.

Since pizza come as a whole number.

And 2. 75 is nearly equal to 3.00

Hence, Cyrus needs to order 3 full pizzas to feed his 11 friends .

6 0

3 years ago

PLZZZZZZZZZZ HELP ME WITH THIS

Pavlova-9 [17]

Answer:

First answer:

-16y=-19x+12

16y=19x-12

y=19/16x-3/4

Second answer:

8y=-15x-9

y=-15/8x-9/8

7 0

2 years ago

Your favorite video game just went on sale for 33% off.

abruzzese [7]

Answer:

$40.20

Step-by-step explanation:

60 / 100 = 0.6

0.6 x 33 = 29.8

60 - 29.8 = 40.2

Thus he price after the discount would be $40.20

3 0

3 years ago

M∠LONm, angle, L, O, N is a straight angle.

Ne4ueva [31]

Answer: 41

Step-by-step explanation:

5 0

3 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

4 years ago