Question

Electrical poles that carry elecrtical wire seem to get smaller the farther away they are. Find the apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole

Answer 1

Answer:

The answer to the question is;

Then the apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole is $\frac{50*x}{(x + 100*n)}$ .

Step-by-step explanation:

To answer the question we have

Let the location of the closest pole = x

Let the height of the closest pole = h feet

Also let the actual  height of the pole at location 100×n feet away be 50 feet

Where n = 1, 2, 3, ...∞

Then we have by taking tangent of the similar triangles so formed by the poles

Then h/x = 50/(x +100·n)

Therefore h = 50 × x/(x +100·n) = 50·x ÷(x + 100·n) = $50 \frac{x}{(x + 100n)}$ feet

The apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole is 50·x /(x+100·n) where n is the number of 100 feet further away the pole is e.g when n = 1 we have

h = 50·x /(x+100·1)  = 50·x /(x+100)